Calculating Work Done by Kinetic Frictional Force on a Coasting Skier

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SUMMARY

The discussion focuses on calculating the work done by the kinetic frictional force on a skier coasting up a slope. The skier has a mass of 67.9 kg and starts with an initial speed of 8.54 m/s, coasting a distance of 1.94 m up a hill inclined at 27.7 degrees, ultimately reducing speed to 3.15 m/s. Participants emphasize using the kinetic energy (KE) formula, KE = 0.5mv², and the conservation of energy equation, which relates changes in kinetic energy (KE) and potential energy (PE) to the work done by friction (Q).

PREREQUISITES
  • Understanding of kinetic energy calculations using KE = 0.5mv²
  • Knowledge of potential energy concepts in physics
  • Familiarity with the conservation of energy principle
  • Basic grasp of forces acting on objects in motion, specifically friction
NEXT STEPS
  • Study the conservation of energy in mechanical systems
  • Learn how to calculate work done by frictional forces
  • Explore the relationship between kinetic energy and potential energy
  • Investigate the effects of incline angles on motion and energy
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Students studying physics, particularly those focusing on mechanics and energy conservation, as well as educators seeking to clarify concepts related to friction and motion.

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A 67.9kg skier coasts up a snow-covered hill that makes an angle of 27.7o with the horizontal. The initial speed of the skier is 8.54m/s. After coasting a distance of 1.94m up the slope, the speed of the skier is 3.15m/s. Calculate the work done by the kinetic frictional force that acts on the skis.

This is a problem that I seem to keep getting wrong. I have spent over an hour on it now...

so far I have come up with that i will find my initial and final KE by .5mv^2

How do I incorporate the conservational equation into this?

My mind is jumbled

Thanks.
 
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change in KE = (-) change in PE + Q. (Q is heat generated through work done by friction)
 

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