Calculating Work Done in a Closed Piston Cylinder Device with V^1.2 = Constant

  • Thread starter Thread starter junglep
  • Start date Start date
  • Tags Tags
    Thermodynamics
Click For Summary

Homework Help Overview

The problem involves calculating the work done during the expansion of air in a closed piston cylinder device, where the relationship between pressure and volume is defined by the equation PV^1.2 = constant. The initial conditions include a pressure of 1 MPa and a temperature of 327 degrees Celsius, with the air expanding to a final pressure of 200 kPa.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the nature of the process, with some suggesting it may be adiabatic due to the given relationship. Others question the implications of the V^1.2 term and seek clarification on its validity and meaning.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the process and questioning the assumptions involved. Some have offered insights regarding the adiabatic nature of the process, while others are seeking further clarification on the equation itself.

Contextual Notes

There is uncertainty regarding the temperature conditions during the process, as one participant raises a question about whether the temperature is constant. Additionally, the specific nature of the V^1.2 relationship is being examined for its correctness and implications.

junglep
Messages
8
Reaction score
0
hey guys got this question that i have been stuck on for a while.

air is expanded from 1M Pa at 327 degrees celsius to 200kPa in a closed piston cylinder device. for the process PV^1.2 = constant. calculate the work done during this process

any help will be welcomed

cheers
 
Physics news on Phys.org
temperature constant? work done= -pV ?
 
if [P(V^1.2) = constant] this is an adibatic process which means that there is no heat added or taken away.
 
I have not encountered something like V^1.2 before. Is that right? If so can someone enlighten me about it?
 

Similar threads

Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
6K
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 8 ·
Replies
8
Views
4K