Calculating Work Needed to Compress Spring

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Homework Help Overview

The problem involves calculating the work required to compress a spring, given the work done to stretch it a certain distance. The subject area pertains to mechanics, specifically the behavior of springs and the work-energy principle.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of the spring potential energy formula to find the spring constant and subsequently calculate the work for a different compression distance. There is uncertainty about the calculated spring constant and the implications of the work done for different distances.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and questioning the validity of their calculations. Some participants suggest that the energy required should increase with greater compression, indicating a need for further examination of the assumptions made.

Contextual Notes

Participants are working under the constraints of the problem statement and are attempting to reconcile their calculations with the physical principles governing spring mechanics. There is a noted concern about the unusually high value of the spring constant derived from the initial work done.

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Homework Statement


To stretch a spring a distance 2.96 cm from its unstretched length, an amount of work of 11.3 J must be done.

How much work must be done to compress this spring a distance 4.01 cm from its unstretched length?

I did this but am not sure if it is correct.

Us = 1/2K[tex]\Delta[/tex]X2

2.96cm = .0296m

4.01cm = .0401m

[tex]\Delta[/tex]X = .0105m

What do I do from here? Would Us = 11.3J?
 
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Using known amount of work done, using relevant equation, find the spring constant k.
Using this value of k, find the work done in the second case.
 
With the equation [tex]U_{s}=\frac{1}{2}kx^2[/tex], you know all but one value, k. Find out what it is. Then for the second part, you'll have all values except [tex]U_{s}[/tex]. which you can solve for.
 
11.3J = 1/2K(.0296m)2

K=25794 N/m but that is an insanely high number, so I do not think that is correct.

Regardless

[tex] U_{s}=\frac{1}{2}kx^2[/tex]

Us = 1/2(25794 N/m)(.0105m)2

=1.42 J ?
 
For the second part, x is from the unstretched length. So x = 4.01 cm.
 
I think that 1.42j is wrong.If you think that in order to move 2.96 you need 11.3j energy.So in order to move it more you would need more energy.
 
That's an way to understand that there is a error.I hope i helped
 
Us = 1/2(25794 N/m)(.0401m)2

=20.7J ?
 

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