Calculating Work Required to Lift a Hanging Chain

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SUMMARY

The discussion focuses on calculating the work required to lift a 30 ft hanging chain with a density of 5 lb/ft³. The user attempted to solve the integral \(\int^{0}_{-30} \frac{5}{30}y \, dy\) and arrived at a result of 75 lb/ft, which they questioned for accuracy. The conversation highlights the need for clarity in applying calculus principles to physics problems, particularly in the context of work done against gravity.

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  • Understanding of calculus, specifically integration techniques.
  • Familiarity with physics concepts related to work and force.
  • Knowledge of the properties of chains and their density.
  • Ability to set up and evaluate definite integrals.
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  • Review the principles of work in physics, focusing on lifting objects against gravity.
  • Study integration techniques in calculus, particularly for variable density problems.
  • Explore examples of similar problems involving hanging chains and work calculations.
  • Learn about the application of definite integrals in real-world physics scenarios.
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Students of physics and calculus, educators teaching integration in the context of physics, and anyone interested in solving problems related to work and force in mechanical systems.

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Homework Statement


A chain hangs verticaly from a building. The chain is 30 ft long and is 5 lb/ft3, how much work is needed ot lift the bottom of the chain to the top.

Homework Equations


If you put the axis where the chain is hanging your limits would be 0 and -30

The Attempt at a Solution


So I tried \int^{0}_{-30}5/30y dy

Then I get 1/12y2 and solve it for 0 and -30 and get 75 lb/ft, but it doesn't seem right.

(sorry if I didnt use the templete right, I'm a noob at this)
 
Physics news on Phys.org
I'm moving this to physics. Questions based on physics principles whilst still using calculus should be put in the intro physics homework forum.
 
Nobody?

Not even a "no your wrong" or "yes that's right"?
 

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