Calculating Work, Speed & Power of a Car Climbing a Hill

Click For Summary

Homework Help Overview

The discussion revolves around a physics problem involving a car of mass 1100 kg climbing a hill of altitude 50 m, reaching a speed of 25 m/s at the top, and then coasting down to an altitude of 15 m. Participants are exploring concepts related to work, speed, power, and energy transformations, specifically focusing on kinetic energy, potential energy, and the work done by the engine.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the work-energy principle, questioning how to calculate work done by the engine and the relationship between kinetic and potential energy. Some express confusion about determining final velocities and the impact of energy changes during the climb and descent.

Discussion Status

Several participants are actively engaging with the problem, attempting to clarify their understanding of energy concepts and the equations involved. There is a recognition that the work done by the engine includes both the change in potential energy and kinetic energy. However, there is no explicit consensus on the approach to take or the specific equations to use.

Contextual Notes

Participants note that the problem assumes negligible friction and air resistance initially, but later introduces a scenario where these forces are considered, complicating the calculations. The original poster expresses uncertainty about where to start and what equations to apply, indicating a need for foundational understanding of the concepts involved.

xupe33jrm
Messages
14
Reaction score
0
1. A car of mass 1100 kg starts from rest at sea level and climbs a hill of altitude 50 m. At the top of the hill the car has a speed of 25 m/s. From the top of the hill the driver turns off the engine and coasts down to an altitude of 15 m. Assume the friction and the air resistance to be negligibly small.

a. work produced by the engine of the car?
b.Speed of the car when the altitude is 15m
c. After passing the altitude of 15m, the driver climbs up again, without turning the engine on. In this case, the speed of the car would be zero
at an altitude of?
d. In reality the friction and the air resistance are not zero. If the work needed to overcome thefriction and the air resistance is 5.2×105 Joules, the answer to part (a) would change. In thiscase, the work produced by the engine to climb to 50 m and have a speed of 25 m/s at the topwould be?
e. In part (d) the car reaches the top of the hill in 80 seconds. The power developed by the
engine is?

I have the answers, I am just confused where to start and what equations to use. Please help me get started on these!
 
Physics news on Phys.org
xupe33jrm said:
1. A car of mass 1100 kg starts from rest at sea level and climbs a hill of altitude 50 m. At the top of the hill the car has a speed of 25 m/s. From the top of the hill the driver turns off the engine and coasts down to an altitude of 15 m. Assume the friction and the air resistance to be negligibly small.

a. work produced by the engine of the car?
b.Speed of the car when the altitude is 15m
c. After passing the altitude of 15m, the driver climbs up again, without turning the engine on. In this case, the speed of the car would be zero
at an altitude of?
d. In reality the friction and the air resistance are not zero. If the work needed to overcome thefriction and the air resistance is 5.2×105 Joules, the answer to part (a) would change. In thiscase, the work produced by the engine to climb to 50 m and have a speed of 25 m/s at the topwould be?
e. In part (d) the car reaches the top of the hill in 80 seconds. The power developed by the
engine is?

I have the answers, I am just confused where to start and what equations to use. Please help me get started on these!

What can you tell us about Total Energy TE, Potential Energy PE, Kinetic Energy KE, and Work W? How are they related? What are the equations for each?
 
On A I tried to use the Work equation W=KE(final)-KE(initial), with KE(f) = .5mv^2(f) and initial being same but using initial velocity. How do I find V final?
 
xupe33jrm said:
On A I tried to use the Work equation W=KE(final)-KE(initial), with KE(f) = .5mv^2(f) and initial being same but using initial velocity. How do I find V final?

The car starts from rest.

EDIT -- and there is also a change in PE.
 
I am spinning in circles. What am I missing?
 
xupe33jrm said:
I am spinning in circles. What am I missing?

The work done by the engine climbing the hill is the sum of the change in PE and the change in KE. Write that equation and solve for the work done climbing the hill.
 
xupe33jrm said:
I am spinning in circles. What am I missing?

Part a) is only about the climb to 50m because the engine is turned off after that, so v_final is 25 m/s as given in the problem.

The car also gains potential energy, and the work to do this is also produced by the engine.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
Replies
3
Views
1K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
5K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 19 ·
Replies
19
Views
11K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K