Calculating Work to Stretch a Spring from 30cm to 41cm

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SUMMARY

The discussion centers on calculating the work required to stretch a spring from 30 cm to 41 cm. Given that a force of 21 N is needed to stretch the spring to 35 cm, the spring constant k is determined to be 60 N/m. The work done, calculated through integration of the force function from 0 to 0.11 m, results in a final answer of 0.36 Joules, rounded to the nearest hundredth.

PREREQUISITES
  • Understanding of Hooke's Law and spring constants
  • Basic knowledge of calculus, specifically integration
  • Familiarity with units of work, specifically Joules
  • Ability to perform unit conversions (cm to m)
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  • Study Hooke's Law and its applications in physics
  • Learn integration techniques for calculating work done by variable forces
  • Explore problems involving spring mechanics and energy storage
  • Review unit conversion methods for physics calculations
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Students in physics courses, particularly those studying mechanics, as well as educators looking for examples of work calculations involving springs.

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Homework Statement


A spring has a natural length of 30 cm. If a 21 N force is required to keep it stretched to a length of 35 cm, how much work W is required to stretch it from 30 cm to 41 cm? (Round your answer to the nearest hundredth.)


Homework Equations



41cm-30cm=11cm so its .11m
21n=.35mk k= 21/.35 k=60 so f(x)= 0 to .11 of 60x so the integration is 30x^2 |0 to .11

so it should be 30(.11)^2 = 363/1000


The Attempt at a Solution

 
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What is your question?

Yes, what you have doneis correct. Since you are told to "Round your answer to the nearest hundredth." your answer should be 0.36 Joules. (Don't forget the units, "Joules"- that's an important part of the answer.
 

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