Calculating Yield of CuSO4 Crystals from Reaction of H2SO4 and CUO

[matthew77ask]

I was tasked to calculate the yield of CuSO4 by the reaction of H2SO4 and CUO.
My equation says the it should get CUSO4 and H2O.

But should we use CUSO4.5H2O for theoretical yield instead since it is a crystal that we are calculating - if so then I could not balance the equation...

what should I use...

many thanks

 

[Borek]

CuSO₄.5H^sO.

 

[Borek]

what should I use...

CuSO₄.5H₂O.

 

[matthew77ask]

Hi,

Logically CuSO4.5H2O., but

If I use
CuSO4.5H2O
then what to display in the equation ?

and how to balance it? or just balance without 5H20?
[why?]

 

[Borek]

Just balance with water, you are performing the experiment in solution - plenty of water around and it is built into the crystals.

 

[matthew77ask]

Just balance with water, you are performing the experiment in solution - plenty of water around and it is built into the crystals.

5CuO + 5H₂SO₄ --> 5CuSO₄ + 5H₂O

CuSO₄ + 5H₂O --> CuSO₄.5H₂O

5CuO + 5H₂O --> CuSO₄.5H₂O

correct?

thanks.

 

[Borek]

Coefficients should be lowest possible - so the first one is wrong.

Second is OK.

Third is not balanced, which is obvious at first sight - there is no sulfur on the left.

 

[matthew77ask]

Opps!
I am trying to combine the two equations:

5CuO + 5H₂SO₄ --> 5CuSO₄ + 5H₂O

CuSO₄ + 5H₂O --> CuSO₄.5H₂O
Adding them

5CuSO₄ + 5H₂O --> CuSO₄.5H₂O

correct?

thanks.

 

[matthew77ask]

Also, when we use CuSO₄ for reaction calculations, when we use Mr(CuSO₄) and when do we use Mr(CuSO₄.5H₂0) ?

seems that all CuSO₄ are blue - containing the 5H₂O

Many thanks...

 

[Borek]

Try with

CuO + H₂SO₄ + H₂O ->