Calculation of Counterbalance Mass

Click For Summary
SUMMARY

The discussion centers on calculating the counterbalance mass (m2) in a mechanical system involving two links, where m2 is constrained to vertical movement. The final formula derived for m2 is m2 = (m1) * (d1/d2) * (1/2), indicating that m2's value is independent of the angle (Theta). However, participants emphasize that the mechanics require both instances of Theta to be equal, affecting the balance of forces in the system.

PREREQUISITES
  • Understanding of mechanical systems and constraints
  • Knowledge of trigonometric functions in physics
  • Familiarity with mass and force balance equations
  • Basic principles of linear motion and bearings
NEXT STEPS
  • Study the effects of angular displacement on mass distribution in mechanical systems
  • Learn about the principles of static equilibrium in physics
  • Explore advanced topics in dynamics, focusing on force balance equations
  • Investigate the use of linear bearings in constrained motion systems
USEFUL FOR

Mechanical engineers, physics students, and anyone involved in designing or analyzing mechanical systems with counterbalance mechanisms.

bsheikho
Messages
51
Reaction score
4
Hi,

I've been grappling with a calculation that appears to give me a good result, however my gut feeling says other wise. Could someone please check the layout and possibly confirm my final answer. Attached is the layout of the system.

The system: -There is a long arm, d1+d2 is one link. then end of d2 to m2 is the second link.
-m2 is constrained in all directions except vertical up/down movement. (by putting the mass on a linear shaft with linear bearings)
The goal is to calculate m2, everything else is given, and Theta is a variable.

my final answer i reach to is: m2= (m1)*(d1/d2)*(1/2)

The point is that it seems that the mass of object two is independent of the angle. and can be fixed, however I have a feeling that tells me that its not that simple.

I can also upload how I got the final answer, but I'd prefer to see how others would tackle the situation.

Any help is appreciated.
Many Thanks!.
 

Attachments

Last edited:
Physics news on Phys.org
I agree with your answer.
The mechanics require both instances of ##\theta## to be the same, increasing the angle lowers m2 by ##2d_2 \cos(\theta) d\theta## and raises m1 by ##d_1 \cos(\theta) d\theta##. That leads to balance with the condition you posted.
 
  • Like
Likes   Reactions: bsheikho
mfb said:
I agree with your answer.
The mechanics require both instances of ##\theta## to be the same, increasing the angle lowers m2 by ##2d_2 \cos(\theta) d\theta## and raises m1 by ##d_1 \cos(\theta) d\theta##. That leads to balance with the condition you posted.

Excellent! Thank you.
 

Similar threads

Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
6K
Replies
6
Views
4K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K