Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Calculation of equilibrium using fugacities

  1. Sep 24, 2011 #1
    Its been a while since I took thermo. I was looking through my notes regarding fugacity at chemical equilibrium. There was a clever algorithm used to determine whether the pure compound was at equilibrium based upon the varying pressure with a constant temperature. It had the calculation "(fL/fv)-1" display values, fL being fugacity of the liquid and fv being the fugacity of the vapor. After several inputs of different pressures this calculation will approach 0. Now if "(fL/fv)-1" equals zero then fugacities are equal yielding a chemical equilibrium.

    Now if my memory serves there is a reason why we use "(fL/fv)-1" in lieu of "(fv/fL)-1". I am not sure why fL has to be in the numerator. If someone can assist me or show me the right direction I would greatly appreciate it.
     
  2. jcsd
  3. Oct 5, 2011 #2

    danago

    User Avatar
    Gold Member

Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook