How to Calculate the Heat of Hydration of Copper(II) Sulphate?

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SUMMARY

The heat of hydration of copper(II) sulfate can be calculated using the temperature changes observed when dissolving anhydrous copper(II) sulfate and copper(II) sulfate pentahydrate in water. When 8.00g of anhydrous copper(II) sulfate is dissolved, the temperature increases by 2K, indicating an exothermic reaction. Conversely, dissolving 12.5g of copper(II) sulfate pentahydrate results in a temperature decrease of 1K, indicating an endothermic reaction. The heat of hydration can be determined using the formula: (mass of solution * specific heat * temperature change) = heat of hydration (kJ/mol) * number of moles of salt reacting.

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  • Understanding of calorimetry principles
  • Knowledge of exothermic and endothermic reactions
  • Familiarity with molar mass calculations
  • Basic skills in using specific heat capacity formulas
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  • Learn how to calculate molar mass of copper(II) sulfate and its hydrate forms
  • Study calorimetry techniques for measuring heat changes in chemical reactions
  • Explore the concept of enthalpy changes in hydration reactions
  • Review specific heat capacity values for common substances
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Chemistry students, laboratory technicians, and educators involved in thermodynamics and hydration reaction studies will benefit from this discussion.

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How do I calculate the heat of hydration of of copper(II)sulphate knowing that when I dissolve anhydrous copper(II)sulphate temperature changes by 2K and when I dissolve copper(II)sulphate pentahydrate in water temperature decreases by 1K.

We are told to assume that 1cm cubed of water is equivalent to 1gram.

The mass of copper(II)sulphate pentahydrate used is 12.5g and the mass of anhydrous copper(II)sulphate is 8.00g

I need to calculate the heat of hydration from the given data? and I can't do it... so please help people.
 
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This might give some insight

http://www.rit.edu/~axlsch/classes/schp445/Hydrate%20lab.pdf

Are all the data provided. I would expect mass of the water is needed.

The heat given off by hydration raises the temperature of the solution. (mass of the solution * specific heat * temperature change) = heat of hydration (kJ/mol) * no. of moles of salt reacting

One reaction is exothermic and the other is endothermic

See also - http://www2.wwnorton.com/college/chemistry/gilbert/concepts/chapter13/ch13_1.htm
 
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nathaniell said:
How do I calculate the heat of hydration of of copper(II)sulphate knowing that when I dissolve anhydrous copper(II)sulphate temperature changes by 2K and when I dissolve copper(II)sulphate pentahydrate in water temperature decreases by 1K.

We are told to assume that 1cm cubed of water is equivalent to 1gram.

The mass of copper(II)sulphate pentahydrate used is 12.5g and the mass of anhydrous copper(II)sulphate is 8.00g

I need to calculate the heat of hydration from the given data? and I can't do it... so please help people.
Henceforth, please make use of the template, and include your thoughts/attempts at solving the problem.
 

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