Calculation of Proper Acceleration

TrickyDicky · Oct 11, 2012

Mentz114 said:

I've edited my post ! It's the symmetrized covar. diff. that is zero, isn't it ?

Yes, that is actually equivalent to the Lie derivative of the metric wrt the Killing field being zero.

Mentz114 · Oct 11, 2012

George Jones said:

https://www.physicsforums.com/showthread.php?p=2625593\#post2625593

George, as academic jokes go that's pretty funny.

TrickDicky said:

Yes, that is actually equivalent to the Lie derivative of the metric wrt the Killing field being zero.

Argh ! Information overload.

Seriously, is it the case taht using the covariant derivative to test for geodesics will be OK if they are geodesic congruences - which I take to mean that the vector is extendable to a field.

Calculation of Proper Acceleration

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