Calculation of the reduced stiffness of a simple suspension

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SUMMARY

The discussion centers on calculating the reduced stiffness of a front suspension using the formula k_f = k/cos²(ε). Participants clarify that the vertical stroke is proportional to the inclined stroke multiplied by cos(ε), leading to the conclusion that the vertical stiffness (k_vertical) can be expressed as k_vertical = N_f / (Vertical stroke) = N_f / (Inclined stroke) * cos(ε). The relationship indicates that the vertical stiffness is dependent on the angle ε and the force N_f applied to the spring.

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Semat10
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Hello,

I have a problem with reducing a stiffness of a front suspension. Unfortunately I don't understand how to get the reduced stiffness on the right side in the picture. (k_f=k/cos^2E)

front_suspension.jpg


Thanks in advance for your help.

Many greetings,
Semat10
 
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The vertical stroke equals the inclined stroke times the cosine of angle ε.
 
Hello,

I was thinking the same thing but I don't know where the square came from?

Many greetings
 
The force of the vertical spring must be less than ##N_f*cos (ε)## ; therefore, the vertical stroke must be proportionally smaller ##(cos (ε))## than the inclined one (accounted for twice).

##k_{vertical} = N_f / {Vertical~stroke} = N_f / {Inclined~stroke}*cos (ε)##

##k_{vertical}/k_{inclined}=?##
 
Last edited:

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