Calculation of work done by a variable force

Click For Summary
The discussion focuses on the calculation of work done by variable forces, specifically addressing the integration of force acting at varying angles along a path. It raises concerns about the assumption that the angle theta remains constant, arguing that integrating without accounting for the changing angle could yield inaccurate results. Participants clarify that while theta is variable, the integration is valid as long as it is treated correctly within the integral. The direction of the force is suggested to depend on the curvature of the path, with different forces potentially acting simultaneously. Overall, the conversation emphasizes the importance of understanding the variability of both force magnitude and direction in work calculations.
navneet9431
Gold Member
Messages
107
Reaction score
9

Homework Statement


See the explanation of work done by variable forces given in my textbook.
IMG_20180815_085025.jpg

For calculation of work done by variable forces the author analyses only a small fraction of displacement "ds".
And then he makes **assumption** that the force is acting on the particle at an angle theta and that too in the *upward* direction.And then he integrates them.
My question is how integrating them would give us the total work done by the variable force.Because at different positions the angle at which the force is acting would change.It would not be 'theta' for all instants.
And my next question is that how should we determine in which direction the force is acting?
Like in my book the author assumed that it would act like this(in the upward direction),
IMG_20180815_090208.jpg

So what if I say that the force would not act like that but would act like this in the downward direction?
Screenshot_2018-08-15-09-05-50-618_com.hashlearn.now.jpg


Homework Equations



W=Fcos(theta)*S

The Attempt at a Solution


I think that the direction of force should be determined by the curve if the path.If the path bends inwards then the force would act downwards and if the path is bending upwards then the force would act upwards.
Is my thinking correct?
I will be thankful for any help!
 

Attachments

  • IMG_20180815_085025.jpg
    IMG_20180815_085025.jpg
    33 KB · Views: 2,417
  • IMG_20180815_090026.jpg
    IMG_20180815_090026.jpg
    23 KB · Views: 445
  • IMG_20180815_090208.jpg
    IMG_20180815_090208.jpg
    39.4 KB · Views: 929
  • Screenshot_2018-08-15-09-05-50-618_com.hashlearn.now.jpg
    Screenshot_2018-08-15-09-05-50-618_com.hashlearn.now.jpg
    14.7 KB · Views: 921
Physics news on Phys.org
navneet9431 said:
at different positions the angle at which the force is acting would change
The author allows that θ is a variable.
 
Ok then integrating them would be wrong as the angle would be changing continuously at every instant.
So integrating them would not give us the actual work done,but slightly different value.
Am I correct?
haruspex said:
The author allows that θ is a variable.
 
navneet9431 said:
then integrating them would be wrong
No, integrating is fine as long as it is treated as a variable. The mistake would be to move the cos(θ) term outside of the integral.
 
  • Like
Likes navneet9431
haruspex said:
No, integrating is fine as long as it is treated as a variable. The mistake would be to move the cos(θ) term outside of the integral.
Thanks!
Now check my this reasoning,is it correct?

"I think that the direction of force should be determined by the curve of the path.If the path bends inwards then the force would act downwards and if the path is bending upwards then the force would act upwards."
 
navneet9431 said:
the direction of force should be determined by the curve if [of] the path
The author is not assuming the force is constant either, neither in magnitude nor direction.
 
navneet9431 said:
"I think that the direction of force should be determined by the curve of the path.If the path bends inwards then the force would act downwards and if the path is bending upwards then the force would act upwards."
You are assuming that this force is the only force acting on the object. This is not necessarily true.
 
A representative diagram showing a force in a direction does not mean that the force is always in that direction, or has that magnitude. In general, both the magnitude and direction (θ) are variables and are part of the integrand. Note also that ds itself changes as you follow the path. Also note post #7 above, There could be three different forces acting on the object in different directions, and you may need to calculate the work done by one of the forces.
 
The author is assuming you already know (in advance) the magnitude and direction of the force along the path, in terms of their variation with path position s.
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
920
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 57 ·
2
Replies
57
Views
5K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
6
Views
2K
  • · Replies 19 ·
Replies
19
Views
1K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 18 ·
Replies
18
Views
2K
Replies
25
Views
3K
Replies
2
Views
1K