- #1
connormaphone
- 5
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I have been given a physics assignment which requires that I go over the physics of why 40km/h is a better speed to be followed in a school zone rather than 50km/h. (must include calculations for stopping distances etc.)
I used the formula Vo ^ 2 / 2 x μ x g.
It should give me the stopping distance if I am correct, Vo being the inital velocity, μ the friction coefficient and g for gravity. I first tried using 40km/h for Vo, .7 for μ and 9.8 for g.
40^2/2x.7x9.8
I use this and end up with 116.61...kilometres, this is evidently wrong and I am not sure what I am doing wrong as it should come out to 20-30 metres.
Can somebody please help?
Thanks.
(P.S I am in grade 11, so go easy on me )
I used the formula Vo ^ 2 / 2 x μ x g.
It should give me the stopping distance if I am correct, Vo being the inital velocity, μ the friction coefficient and g for gravity. I first tried using 40km/h for Vo, .7 for μ and 9.8 for g.
40^2/2x.7x9.8
I use this and end up with 116.61...kilometres, this is evidently wrong and I am not sure what I am doing wrong as it should come out to 20-30 metres.
Can somebody please help?
Thanks.
(P.S I am in grade 11, so go easy on me )