Calculus 1 finding absolute max and min

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SUMMARY

The discussion centers on calculating the absolute maximum and minimum values of the shuttle's acceleration using the velocity model v(t) = 0.001397167t³ - 0.080965t² + 16.02t - 0.39, derived from a University of Rochester student's calculations. The derivative v'(t) = 0.004191201t² - 0.16193t + 16.02 was found, but the critical points yielded complex solutions, indicating no real solutions exist. Consequently, the maximum and minimum values must be evaluated at the endpoints of the interval from t = 0 to t = 79.2 seconds.

PREREQUISITES
  • Understanding of calculus concepts, specifically derivatives and critical points
  • Familiarity with polynomial functions and their properties
  • Knowledge of the quadratic formula and its application
  • Ability to evaluate functions at specific intervals
NEXT STEPS
  • Study the application of the Mean Value Theorem in calculus
  • Learn how to analyze polynomial functions for extrema
  • Explore the concept of acceleration as the derivative of velocity
  • Investigate the use of computational tools like Wolfram Alpha for calculus problems
USEFUL FOR

Students studying calculus, particularly those focusing on optimization problems and the analysis of polynomial functions. This discussion is beneficial for anyone needing to understand how to find absolute extrema in a given interval.

Wm_Davies
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A University of Rochester student decided to depart from Earth after his graduation to find work on Mars. Before building a shuttle, he conducted careful calculations. A model for the velocity of the shuttle, from liftoff at t = 0 s until the solid rocket boosters were jettisoned at t = 79.2 s, is given by

v(t)=0.001397167t3−0.080965t2+16.02t−039

(in feet per second). Using this model, estimate
the absolute maximum value
and absolute minimum value (I found this through using Wolfram Alpha I don't understand how I get it though which is a problem)
of the acceleration of the shuttle between liftoff and the jettisoning of the boosters.


I got the derivative to be

v'(t)= 0.004191201t2-0.16193t+16.02

I imagine that I would have to find the critical points of this to get the max and min

So I used the quadriatic formula but I am getting imaginary numbers when I do this so I am having trouble coming up with the absolute maximum and minimum any help would be appreciated.
 
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I assume you're looking for the absolute maximum value of the velocity.

For v(t), why do you have 039 as the constant term? Is that 39 or is there a decimal point missing in it?

Your v'(t) looks about right, and I find also that the solutions to v'(t) = 0 are complex, meaning that there are no real solutions to v'(t) = 0. This means that v'(t) > 0 for all t or that v'(t) < 0 for all t (not likely).

Since there are no times for which v'(t) = 0, to find the maximum and minimum values of v(t), check the endpoints of your domain, which is implied in your problem description.
 
it is supposed to be 0.39 instead of 39. I will try that what you suggest.
 

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