Calculus and Vectors - Limits and Derivatives

ttpp1124 · Apr 24, 2020

Handwritten working for a limit problem: as x approaches 3, (5x^2+8x-4)/(x^2-3x+k) becomes (5(3^2)+8(3)-4)/(3^2-3(3)+k), which equals (75+24-4)/k = 95/k. Note: For 95/k to be a real value, k cannot be zero.

Mark44 · Apr 24, 2020

ttpp1124 said:

Homework Statement:: Find the value of k.
I solved it, but would it help to justify if I mentioned the fact that k can be any non-zero real value?
Relevant Equations:: n/a

View attachment 261336

I agree with your conclusion, but you work leading to that is incorrect. ##5*3^2 \ne 75##.

ttpp1124 · Apr 24, 2020

Mark44 said:

I agree with your conclusion, but you work leading to that is incorrect. ##5*3^2 \ne 75##.

whoops, it's supposed to be 65/k. Thank you!

Calculus and Vectors - Limits and Derivatives

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