Calculus-I: discontinuity of piecewise function HW problem

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Homework Help Overview

The discussion revolves around the continuity of a piecewise function as part of a Calculus I homework problem. Participants are examining the function's behavior at specified intervals and questioning the correctness of their interpretations and solutions.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are questioning the continuity of the piecewise function, particularly at the boundaries and in the intervals where the function is defined. There are discussions about whether the function is continuous or discontinuous and the implications of simplifying the second function.

Discussion Status

Some participants have offered clarifications and suggestions for further investigation, such as checking for discontinuities beyond the boundaries of the piecewise definition. There is an acknowledgment of the need for a homework template and a general sense of understanding developing among participants.

Contextual Notes

There are mentions of specific intervals (x < 0 and x > 3) where the function is defined, and the original poster has noted an error in their piecewise definition. The homework template's absence has been pointed out as a concern for future posts.

grey2q
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Screenshot of my homework problem along with my solution so far. I'm not sure if I'm doing this correctly and if I am... if I'm answering correctly. Thank you. (EDIT: I made 1 small error with the piecewise definition. Ignore the f(x) before g(x).)

mathproblem1.png
 

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grey2q said:
Screenshot of my homework problem along with my solution so far. I'm not sure if I'm doing this correctly and if I am... if I'm answering correctly. Thank you. (EDIT: I made 1 small error with the piecewise definition. Ignore the f(x) before g(x).)

View attachment 219851
What about where x < 0 or where x > 3? Your function is defined on those intervals, as well.

Also, the homework template you deleted is required here. In future posts, please don't delete this template.
 
grey2q said:
Screenshot of my homework problem along with my solution so far. I'm not sure if I'm doing this correctly and if I am... if I'm answering correctly. Thank you. (EDIT: I made 1 small error with the piecewise definition. Ignore the f(x) before g(x).)

View attachment 219851
You have shown that the piecewise function is continuous at the boundaries of the pieces. If you are going to investigate the continuity of the function, you should also find out if there are any other discontinuities.
 
Mark44 said:
What about where x < 0 or where x > 3? Your function is defined on those intervals, as well.

Also, the homework template you deleted is required here. In future posts, please don't delete this template.

Thanks for the response.

I think I understand. So, would it make more sense for me to say that the piecewise function isn't discontinuous? Or that the piecewise function is continuous?

And what about my math? Am I going about this the correct way?
 
grey2q said:
I think I understand. So, would it make more sense for me to say that the piecewise function isn't discontinuous? Or that the piecewise function is continuous?
Right, either way. The function is continuous on the entire real line.

grey2q said:
And what about my math? Am I going about this the correct way?
Looks OK to me.
 
For more clarity I would see whether you could simplify the second function - might bring new insight. :oldwink:
 
epenguin said:
For more clarity I would see whether you could simplify the second function - might bring new insight. :oldwink:
It doesn't in this problem, but the OP might or might not have done this. The second function (the rational expression) is continuous at each point on the interval [0, 3]. @grey2q, did you consider this?
 
Mark44 said:
It doesn't in this problem, but the OP might or might not have done this. The second function (the rational expression) is continuous at each point on the interval [0, 3]. @grey2q, did you consider this?

I did.

Thanks for the help guys. I think I understand now.
 

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