Calculus: Integral along a curve.

Click For Summary
The discussion centers on the misunderstanding of the conditions for a vector field to be conservative. It highlights that even if the curl of the vector field F is zero, the vector field may not be conservative if the domain is not simply connected, as is the case with the annulus A. An example provided is the vector field F(x,y) = (1/(x²+y²))(-y,x), which demonstrates that the line integral around a closed curve can yield a non-zero result despite having a zero curl. The key error in the original reasoning is the assumption that curl being zero guarantees the integral along any closed curve is also zero in non-simply connected domains. Thus, the conclusion is that the non-simply connected nature of A prevents F from being conservative.
LCSphysicist
Messages
644
Reaction score
162
Homework Statement
.
Relevant Equations
.
Let $F = (P(x,y),Q(x,y))$ a field of vector class 1 in the ring $A={(x,y): 4<x²+y²<9}$ and $x,y$ reals.

I am having trouble to understand why this alternative is wrong:

If $ \partial P /\partial y = \partial Q /\partial x$ for every x,y inside A, so $\int_{C} Pdx + Qdy = 0$ for every circumference $\epsilon $ A.

I mean, the condition implies that $Curl F = 0$, and we have that the field of vector is C1, so we don't need to worry with anomalies or problems that could appear as $(...)/0$. In fact, $\int_{C} Pdx + Qdy = \int_{S} \nabla \times F \space ds = \int_{S} 0 \space ds = 0$

Where is my error? If i am wrong, could you give me an example of a vector field that does not satisfies the implication? Where is the error in my demonstration?
 
Physics news on Phys.org
The annulus ##A## is not simply connected, therefore ##\mathbf{F}(x,y) = (P(x,y), Q(x,y))^T## is not a conservative vector field even if ##\dfrac{\partial P}{\partial y} = \dfrac{\partial Q}{\partial x}##. For example, consider the line integral of a vector field ##\mathbf{F}(x,y) = \dfrac{1}{x^2+y^2} (-y,x)^T## around a closed curve ##C: \mathbf{r}(t) = a(\cos{t}, \sin{t})^T## for ##t \in [0, 2\pi]## and with ##a \in (2,3)##.
 
  • Like
Likes LCSphysicist
First, I tried to show that ##f_n## converges uniformly on ##[0,2\pi]##, which is true since ##f_n \rightarrow 0## for ##n \rightarrow \infty## and ##\sigma_n=\mathrm{sup}\left| \frac{\sin\left(\frac{n^2}{n+\frac 15}x\right)}{n^{x^2-3x+3}} \right| \leq \frac{1}{|n^{x^2-3x+3}|} \leq \frac{1}{n^{\frac 34}}\rightarrow 0##. I can't use neither Leibnitz's test nor Abel's test. For Dirichlet's test I would need to show, that ##\sin\left(\frac{n^2}{n+\frac 15}x \right)## has partialy bounded sums...