Calculus of parametric equations (finding surface area)

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The discussion focuses on calculating the surface area of a curve defined by the parametric equations x=e^t sin(t) and y=e^t cos(t) when revolved around the x-axis and y-axis. For the x-axis, the surface area formula involves integrating 2π times the function f(x) multiplied by the square root of 1 plus the derivative squared. For the y-axis, the formula requires integrating 2π times x multiplied by the same square root term. Participants are encouraged to determine the specific forms of f(x) and dx based on the given parametric equations. The conversation emphasizes the importance of understanding the integration process for accurate surface area calculations.
jrg_pz
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I was wondering what the surface area would be when the curve:

x=e^tsint,
and y=e^tcost where (t) is greater than or equal to (0) and (t) is less
or equal to pi divided by (2).
when it is revolved about
a) the x-axis
b) the y-axis (approximation with calc. (how?))
 
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jrg_pz said:
I was wondering what the surface area would be when the curve:

x=e^tsint,
and y=e^tcost where (t) is greater than or equal to (0) and (t) is less
or equal to pi divided by (2).
when it is revolved about
a) the x-axis
b) the y-axis (approximation with calc. (how?))

Around the x-axis you have:

\text{SA}_x=2\pi\int_{a}^{b}f(x)\left(\sqrt{1+f'(x)^2}\right)dx

...the y-axis you have:

\text{SA}_y=2\pi\int_{a}^{b}x\left(\sqrt{1+f'(x)^2}\right)dx

And I assume you can figure out what f(x) and dx are in terms of your parametric equations...
 
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