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Calculus of Variations (Canonical equations)

  1. Feb 25, 2007 #1
    I've been looking at this example for a while now. Could someone help?

    "Take the functional to be

    [itex] J(Y) = \int_{a}^{b} \( \alpha Y'^2 + \beta Y^2) dx [/itex]

    For this

    [itex] F(x,y,y') = \alpha y'^2 + \beta y^2 [/itex]

    and [itex] p = \frac{ \partial F}{\partial y'} = 2 \alpha y' [/itex]
    [itex] \Rightarrow y' = \frac{p}{2 \alpha}[/itex]

    The Hamiltonian H is

    [itex] H = py' - F = \frac {p^2}{4 \alpha} - \beta y^2[/itex]

    So the canonical equations are

    [itex] \frac{dy}{dx} = \frac{ \partial H}{ \partial p} = \frac{p}{2 \alpha} [/itex]
    and

    [itex]- \frac{dp}{dx} = \frac{\partial H} {\partial y} = -2 \beta y [/itex]

    I've also got the Euler Lagrange equation as

    [itex] 2 \beta y - \frac{d}{dx} (2 \alpha y') = 0[/itex]

    How can you tell that the Euler Lagrange equation is equivalent to the Canonical Euler equations in this set example?

    Thanks in advance
     
  2. jcsd
  3. Feb 25, 2007 #2

    dextercioby

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    Differentiate wrt "t" the eqn involving the first derivative of "y" and substitute the first derivative of p from the second and the resulting 2-nd order ODE in "y" will coincide with the Euler-Lagrange eqn for the lagrangian.
     
  4. Feb 25, 2007 #3
    Sorry, what do you mean by this?
     
  5. Feb 25, 2007 #4

    dextercioby

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    Differentiate with respect to "x" (sorry, i thought it was "t", like in physics, where "t" stands for time) the first equation, the one involving dy/dx.
     
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