Calculus of Variations-Hanging String

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The discussion focuses on solving a calculus of variations problem involving a uniform string hanging between two supports. The goal is to minimize the potential energy of the string to derive the curve it forms and determine the vertical distance from the supports to the lowest point of the string. Participants express difficulty in applying the Euler-Lagrange equation and incorporating constraints related to the supports. There is speculation that the shape of the string may resemble a cycloid, but proving this remains challenging. Assistance is requested to clarify the approach and solution methods for this problem.
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Calculus of Variations--Hanging String

Homework Statement



A uniform string of length 2 meters hangs from two supports of the same height, 1 meter
apart. By minimizing the potential energy of the string, find the equation describing the
curve it forms and, in particular, find the vertical distance between the supports and the
lowest point of the string.

Homework Equations


U = λ g \int y(x)dx
0≤ x ≤ 1
S = \int\sqrt{dx^2+dy^2}dt
Euler-Lagrange Equation

The Attempt at a Solution



Been stuck on this one for awhile, tried solving naively by just solving the lagrange equation for potential energy and that obviously got me an answer of U = 0. I also tried to solve the arc length equation for y(x) and I got y'[x] = √3, so that is obviously wrong. I'm not sure how to add the constraints of the supports into the equation. I am probably going to have to parameterize y and x in terms of some other variable.

I have a feeling that the shape is going to be a cycloid...just having a hard time proving it.
 
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Bump^^^ Can i get a hand with this, i saw a similar question posted, with an unclear answer
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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