Calculus problem regarding Thermodynamics HW (entropy for C2H5OH at 348K)

  • #1
Summary:: Seems simple but has me stumped...

[Thread moved from a technical forum, so no Homework Template is shown]

Hello! Im struggling to use an equation given to me. To provide some context, I am trying to work out the entropy for C2H5OH at 348K.

Using provided tabulated data, the entropy (S) for C2H5OH at 298K is 160.7 [J/K].

I have also been given the specific heat capacity at constant pressure (111.46 [J/K]) and have been instructed to assume that it is independent of temp.

I simply cannot understand how to use the equation given to me....

S(T) = (integration sign with limits of 0 to T) Cp / T (derivative dash) * dT(deriv dash)

Any help is greatly appreciated.
 
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Answers and Replies

  • #2
George Jones
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Summary:: Seems simple but has me stumped...

[Thread moved from a technical forum, so no Homework Template is shown]

Hello! Im struggling to use an equation given to me
Hint:
$$\int_0^{T_2} = \int_0^{T_1} + \int_{T_1}^{T_2}$$
 
  • #3
Thanks George, I'll try to apply your hint
 

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