Calculus: Solve indeterminate question up

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SUMMARY

The discussion centers on evaluating the limit of the expression (infinity)^a * e^(-infinity) where a > 1. The consensus is that this expression is an indeterminate form and requires the application of limit techniques to resolve. Specifically, the limit should be approached as limit x->infinity of x^a * e^(-x). The method of finding limits is crucial for correctly interpreting the behavior of the expression as it approaches infinity.

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  • Understanding of limits in calculus
  • Familiarity with indeterminate forms
  • Knowledge of exponential functions
  • Basic skills in manipulating mathematical expressions
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  • Study the concept of indeterminate forms in calculus
  • Learn techniques for evaluating limits, particularly L'Hôpital's Rule
  • Explore the behavior of exponential functions as they approach infinity
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Please help ... I forgot how to do these calculus problem...

Does (infinity)^a * e^(-infinity), where a >1 equal to 0?

If so, why? If not, how to calculate it?
 
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Askhwhelp said:
Please help ... I forgot how to do these calculus problem...

Does (infinity)^a * e^(-infinity), where a >1 equal to 0?

If so, why? If not, how to calculate it?

You do these things by finding limits. 'infinity' by itself doesn't mean much. Do you mean limit x->infinity x^a*e^(-x)? Since you have an indeterminant limit exactly how you approach infinity in each instance of 'infinity' is pretty important.
 

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