Calculus: Solve indeterminate question up

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Please help ... I forgot how to do these calculus problem...

Does (infinity)^a * e^(-infinity), where a >1 equal to 0?

If so, why? If not, how to calculate it?
 
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Askhwhelp said:
Please help ... I forgot how to do these calculus problem...

Does (infinity)^a * e^(-infinity), where a >1 equal to 0?

If so, why? If not, how to calculate it?

You do these things by finding limits. 'infinity' by itself doesn't mean much. Do you mean limit x->infinity x^a*e^(-x)? Since you have an indeterminant limit exactly how you approach infinity in each instance of 'infinity' is pretty important.