Calorimetry: adding ice to water

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SUMMARY

The discussion focuses on a calorimetry problem involving a 53.5 g ice cube at 0°C added to 369 g of water at 21.4°C. The key equation used is Lf*m + Mc ΔT = MC ΔT, where Lf represents the latent heat of fusion, m is the mass of the ice, and Mc and MC are the specific heat capacities of water. The correct approach requires careful setup of the heat transfer equation, ensuring that both ΔT values are accurately represented to solve for the final temperature (T) of the system.

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Homework Statement



A 53.5 g ice cube, initially at 0°C, is dropped into a Styrofoam cup containing 369 g of water, initially at 21.4°C. What is the final temperature of the water, if no heat is transferred to the Styrofoam or the surroundings?

Homework Equations



Lf*m + Mc Delta T = MC Delta T this is the equation am using but can't seem to get a reasonable answer.

The Attempt at a Solution



This seems like a simple problem but I just can not seem to get the correct answer on webassign. Thanks for anyone who helps.
 
Last edited:
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You are on the right track there with the equation.
On the left is the heat required to melt the ice, plus the heat required to heat the water formed from zero to T degrees. [T is final temperature]
On the right is the heat lost by the warm water cooling from 21.4 degrees to T.

If you set up that equation you can solve for T
 
Note: trick is to correctly write both delta T on the left and delta T on the right.
 

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