labview1958
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If an appliance is rated 60W 120V, R=1 ohm. Then I = V/R= 120/1 = 120A. But the household current is 13 A (max). Will the fuse blow?
An appliance rated at 60W and 120V cannot continuously draw 120A, as this exceeds the maximum household current of 13A. The calculations reveal that with a 1 ohm resistor connected to 120V, the current would indeed exceed 13A, causing the fuse to blow. The fuse does not blow instantaneously; it takes a brief moment for the fuse wire to heat up to its melting point, allowing for a temporary surge above the rated current. Understanding the relationship between power, voltage, and current is crucial in electrical systems.
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In reality, more than 13A would flow for a brief time, until the fuse wire is heated up to it's melting point.labview1958 said:If a 1 ohm resistor is connected, the 13A fuse blows. Why? The max. current supplied to the house is 13A. Where does the extra current comes from to blow the fuse?
labview1958 said:If a 1 ohm resistor is connected, the 13A fuse blows. Why? The max. current supplied to the house is 13A. Where does the extra current comes from to blow the fuse?
Redbelly98 said:In reality, more than 13A would flow for a brief time, until the fuse wire is heated up to it's melting point.