Can a Bound be Found for the Error in Higher Order Taylor Series?

[hadron23]

Hello,

I am trying to come up with an expression for a bound on the sum of higher order terms, above second order. Consider the following Taylor expansion of a function f(x) around a point a,

f(x) = f(a) + \frac{f^{(1)}(a)}{1!}(x-a) + \frac{f^{(2)}(a)}{2!}(x-a)^2+ \frac{f^{(3)}(a)}{3!}(x-a)^3+...<br />

Is it possible to come up with a value M such that

<br /> \begin{align}<br /> &amp;\left|\left|f(x) - [f(a) + \frac{f^{(1)}(a)}{1!}(x-a)]\right|\right|_2^2 \le M\\<br /> &amp;\Rightarrow \left|\left|\frac{f^{(2)}(a)}{2!}(x-a)^2+ \frac{f^{(3)}(a)}{3!}(x-a)^3+...\right|\right|_2^2 \le M<br /> \end{align}<br />

That is, come up with an upper bound on the error of the higher order terms.

Thanks

 

[mathman]

I suspect you would need some conditions on the higher derivatives of f(x) at x=a. Otherwise they might get large fast.

 

[hgfalling]

http://en.wikipedia.org/wiki/Taylor's_theorem#Estimates_of_the_remainder