Can a monkey outrun a bullet and still save her litter?

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AI Thread Summary
The discussion revolves around a series of tricky questions and riddles shared among participants. Key questions include the amount of soil in a hole, the safest room for a condemned murderer, and a math challenge involving sequential additions. Participants engage in solving these riddles, offering various answers and reasoning, with some humor and banter included. The thread showcases a mix of logical puzzles and lateral thinking challenges, encouraging creative problem-solving among the members.
  • #151


K.J.Healey said:
is that a safe site? might want to check your adaware.
I don't get a warning when I go there. Perhaps because I am running Mozilla on Linux. I am going to report myself just in case and have the admins remove the link from my post and from yours as well.
 
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  • #152


jimmysnyder said:
Is that the definition of knee and elbow? I thought a knee was the joint in the leg between the femur on one side and the tibia and fibula on the other. And the elbow, the joint between the humerus on the one side and the ulna and radius on the other. That's how it is on me and my kids.

Since this is brainteasers, one might be expected to stretch definitions to get an answer, but for the sake of correctness, yes, the knee is the joint between the femur and tibia (the fibula really isn't contacting the joint directly, but most assume so since it's very close), and the elbow is the joint between the humerus and ulna and radius. While the humerus and femur are similar in appearance (you can distinguish them by details and size, but an untrained eye could easily confuse them), the tibia and ulna are much more distinct in shape.

Again, people also do often confuse the ankles and wrists of quadripeds with knees because of their location, but this is not unique to any single quadriped, so I don't think it would be sufficient to solve the question.
 
  • #153


verty said:
Q: A man is in a room with no windows, no door, no holes in the ceiling and no trapdoors in the floor. How does he escape the room?

When I have heard this previously, it included the addition of a stool or other piece of furniture, such as a chair.

If not, the same answer can be arrived at assuming the man is wearing clothes. In which case, he tears his shirt in half.

He then has two halves.

What do two halves make?

An alternative answer, assuming the presence of a stool, would be to break off one of the legs of the stool, and then "knock himself out".

Perhaps one could do this with his fists as well :)
 
  • #154


Q: A man is in a room with no windows, no door, no holes in the ceiling and no trapdoors in the floor. How does he escape the room?

If he was a mathematician he could define himself to be on the outside.

As far as the bread thing goes, you get 0 slices. When you make the first cut, the bread is not whole anymore.

k
 
  • #155


kenewbie said:
Q: A man is in a room with no windows, no door, no holes in the ceiling and no trapdoors in the floor. How does he escape the room?

If he was a mathematician he could define himself to be on the outside.

As far as the bread thing goes, you get 0 slices. When you make the first cut, the bread is not whole anymore.

k
Yes, but you're now holding one slice.

The answer is 1.
 
  • #156


powergirl said:
Let me ask the Ist Quest:'n.
"1) How much soil is there in a hole measuring one metre by one metre by one metre?"

if it is a hole it contains nothing, it could potentially hold the exact quantity that was removed.
 
  • #157


powergirl said:
:::>A man dressed all in black is walking down a country lane. Suddenly a large black car without any lights on comes round the corner and screeches to a halt.

How did the driver know there was a man in the road?

either it was day time or he stopped after running him down
 
  • #158


throng said:
if it is a hole it contains nothing, it could potentially hold the exact quantity that was removed.
Well, you know the answer but you've over-thought it.

The question is 'how much soil is there in the hole?'. To which the answer, of course, is 'none'.
 
  • #159


DaveC426913 said:
Yes, but you're now holding one slice.

The answer is 1.

Yeah, you are right. The question asked for "slices of 1.5 cm each", and I figured you start by cutting the bread in equal halfs for some reason. Of course, if you make the first cut 1.5 cm from one end, you get a slice of the correct width.

Oh, no wait. I guess one could argue that once you penetrate the crust of the bread, it is not whole anymore, and thus the first slice does not count either :)

k
 
  • #160


kenewbie said:
Oh, no wait. I guess one could argue that once you penetrate the crust of the bread, it is not whole anymore, and thus the first slice does not count either :)
No. An object with a cut in it is still a single object. The whole is not divided until there is more than one piece.
 
  • #161


Maybe I don't get this but haven't all the questions here already been answered around page 4 or 5? So why do people keep posting the same answer? << You could see that as a sociological tricky question, although I'm afraid I don't have an answer for it.
 
  • #162


xtd said:
Maybe I don't get this but haven't all the questions here already been answered around page 4 or 5? So why do people keep posting the same answer? << You could see that as a sociological tricky question, although I'm afraid I don't have an answer for it.
To some, the actual answer is less interesting than the logic by which you arrived at it.

There's some joke somewhere about a mathematician who saw a chair or something on fire, but, having spied the bucket of water next to it, did not use it to put the fire out. His logic was that, since he'd solved the problem logically, physically demonstrating the solution was redundant.

...or something like that...

:biggrin:
 
  • #163


powergirl said:
NOt right;
Can anyone answer this?
2) A murderer is condemned to death. He has to choose between three rooms: The first is full of raging fires, the second is full of assassins with loaded guns, and the third is full of lions that haven't eaten in 3 years. Which room is safest for him?

THE ANSWER IS:

The third room because lions can't live three years without eating anything... so i might be dead so its safe...:cool:
 
  • #164


zidiane said:
truth guy;which door are you gaurding? "the one behind me."
liar guy;which door are you gaurding? "the one behind that guy right there"

Correct me if I'm wrong, but if you asked the guards that question then these could also be outcomes:

1) You ask the guard that only speaks the truth which door his is guarding. The guard will reply, "The door to freedom," or an equally useless answer.
2) You ask the guard that only speaks lies. The guard will reply, "The door to freedom," or something similar.

Is it just me or am I finding a flaw in the logic here?
 
  • #165


powergirl said:
A prisoner is in jail. There are two doors, one leads to freedom one leads to death. There is a guard at each door. One guard always tells the truth, the other always tells lies. The prisoner is allowed one question to either of the guards.
What is the question that will take him to freedom.?

he would ask either one (it doesn't matter which) what door the other gaurd would say. the gaurd would answer and then he would choose the oposite of what the answer to the question was... this would work because let's say guard A tells the truth and gaurd B lies. if he asked guard A what guard B would say, then Guard A would be telling the truth about the other lieing about which one leads to freedom. so let's say door P led to freedom and door Q led to death. Guard A would say that guard B would say that door Q leads to freedom. so he would take door P
if he asked guard B what guard A would say then guard B would be lieing about guard A elling the truth, and would say that guard A would say that door Q leads to freedom, even though guard A wouldn't say that.
either way he would take door P to freedom

btw... I am only 13 ^.^
 
  • #166


can you guys answer this question?

what appears once in a minute, twice in a week, and once in a year?
 
  • #167


~*Tear*~ said:
can you guys answer this question?

what appears once in a minute, twice in a week, and once in a year?
And four times in "a jolly good fellow"
e
 
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  • #168


a bus conductor accidentally knocked down and killed 50 people while driving his bus in a drunken state.
The judge then sentenced him to death penalty by the electric chair.

On his execution date, he requested to have bananas before he died, and so the judge passed him a bundle of fresh bananas. Surprisingly the electric chair did not kill him.

So the next day, he was tried for execution again, and the same, he requested an apple, so the judge gave him a ripe apple. Amazingly, he survived.

Finally, the judge let him go.

Question: how did he survive?
 
  • #169


unscientific said:
a bus conductor accidentally knocked down and killed 50 people while driving his bus in a drunken state.
The judge then sentenced him to death penalty by the electric chair.

On his execution date, he requested to have bananas before he died, and so the judge passed him a bundle of fresh bananas. Surprisingly the electric chair did not kill him.

So the next day, he was tried for execution again, and the same, he requested an apple, so the judge gave him a ripe apple. Amazingly, he survived.

Finally, the judge let him go.

Question: how did he survive?

"the judge passed him a bundle of fresh bananas. Surprisingly the electric chair did not kill him."
"the judge gave him a ripe apple. Amazingly, he survived."

Because handling fruit is not lethal to judges.
 
  • #170


wrong answer.
 
  • #171


What is it?

The manufacturer doesn't want it, the buyer doesn't use it and the user doesn't see it.
 
  • #172


coffin
 
  • #173


Art said:
What is it?

The manufacturer doesn't want it, the buyer doesn't use it and the user doesn't see it.

"fiscal stimuli"
 
  • #174


There's no user, though.
 
  • #175


unscientific said:
a bus conductor accidentally knocked down and killed 50 people while driving his bus in a drunken state.
The judge then sentenced him to death penalty by the electric chair.

On his execution date, he requested to have bananas before he died, and so the judge passed him a bundle of fresh bananas. Surprisingly the electric chair did not kill him.

So the next day, he was tried for execution again, and the same, he requested an apple, so the judge gave him a ripe apple. Amazingly, he survived.

Finally, the judge let him go.

Question: how did he survive?
Need a hint.
My first suspicion is that the bananas and apple are red herrings.
 
  • #176


unscientific said:
a bus conductor accidentally knocked down and killed 50 people while driving his bus in a drunken state.
The judge then sentenced him to death penalty by the electric chair.

On his execution date, he requested to have bananas before he died, and so the judge passed him a bundle of fresh bananas. Surprisingly the electric chair did not kill him.

So the next day, he was tried for execution again, and the same, he requested an apple, so the judge gave him a ripe apple. Amazingly, he survived.

Finally, the judge let him go.

Question: how did he survive?

My attempt:

I'm confused because it says "tried for execution" in the third paragraph, but says it was his "execution date" in the second paragraph. Is he being tried or executed?

The electric chair can't kill him if he's not sitting in it...
 
  • #177


Need a hint.
My first suspicion is that the bananas and apple are red herrings.
Correct - Hint
What kind of conductor was he?


edit - damn now I'm hooked on this thread, as if the famous landmark one isn't bad enough.
 
  • #178


mgb_phys said:
Correct - Hint
What kind of conductor was he?

Wow, that's awful. It's not really a brain teaser, it's just a bad pun.

DaveE
 
  • #179


Pythagorean said:
My attempt:

Well, I thought you might be onto something for a second.

At first I thought 'it doesn't actually say he was convicted, or that he's going to the chair anytime soon, so it's not surprising he;s still alive (why wouldn't he be?)'

Except it does say 'on his execution date', which means he was, in fact, supposed to be executed on the first day and it didn't happen for some reason.
 
  • #180


I got a brilliant few puzzles here:

Hint: All the questions only have one solution.

1: I have a number that is less than one million. Putting a 1 after it makes it three times as large as putting a 1 before it. What is my number?

2: If Adam and Ben worked together to paint a house they would take 12 hours. Adam and Colin as a team would take 15 hours to paint the house and Ben and Colin as a pair would take 20 hours.
Assuming that the rate at which each painter works is not affected by whom he works with, how long would it take to paint the house if they all worked together?

3: Given any three-digit number, x, define f(x) to be
x minus the sum of the squares of the digits of x
What is the maximum possible value of f(x)?

4. A king has some (finite) number of subjects. One day he lines them all up in a row, facing towards the front of the row. He goes from the front of the row to the back, giving each subject a hat - either red or blue.

No subject can see his/her own hat, nor can any subject see behind himself/herself. But a subject can see ALL of the others that come before him/her in line.

So the king has made his way to the back of the line, and now he will ask the person at the back of the line "What color is your hat?" while brandishing a big sword. If answered correctly, the person is freed. If answered incorrectly, the person is beheaded immediately. No communication between subjects is allowed, although they can hear each others' guesses.

You have a chance to meet with the subjects ahead of time - the night before this incident - to give them a strategy that will save the most number of lives (guaranteed, not a probability or expected outcome).
 
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  • #181


mgb_phys said:
Correct - Hint
What kind of conductor was he?
I still don't get it. Is it an electronics pun?
 
  • #182


DaveC426913 said:
I still don't get it. Is it an electronics pun?

The punch line (I looked this up elsewhere) goes something like:

A reporter asked him upon his release whether or not he had found some secret relating fruit to the electric chair.
"No," he replied, "I've just always been a bad conductor."

Very disappointing if you were looking for this to be a bona fide brain teaser.

DaveE
 
  • #183


Georgepowell said:
Hint: All the questions only have one solution.

1: I have a number that is less than one million. Putting a 1 after it makes it three times as large as putting a 1 before it. What is my number?

I already found 2 solutions.

Georgepowell said:
2: If Adam and Ben worked together to paint a house they would take 12 hours. Adam and Colin as a team would take 15 hours to paint the house and Ben and Colin as a pair would take 20 hours.
Assuming that the rate at which each painter works is not affected by whom he works with, how long would it take to paint the house if they all worked together?

Quick algebra yields that the answer is the 2nd digit of the answer to question 1 times the 4th digit of question 1.

Georgepowell said:
3: Given any three-digit number, x, define f(x) to be
x – the sum of the squares of the digits of x
What is the maximum possible value of f(x)?

I'm not sure I understand what the trick is here. Maximizing the sum is as easy as maximizing each term within the sum. Each term is a square of a digit of x, which means maximizing each digit's square. Maximizing a square of a digit simply means maximizing that digit. Hence, 999 = x, making f(x) = 9^2 + 9^2 + 9^2 = 243.

Georgepowell said:
4. A king has some (finite) number of subjects. One day he lines them all up in a row, facing towards the front of the row. He goes from the front of the row to the back, giving each subject a hat - either red or blue.

No subject can see his/her own hat, nor can any subject see behind himself/herself. But a subject can see ALL of the others that come before him/her in line.

So the king has made his way to the back of the line, and now he will ask the person at the back of the line "What color is your hat?" while brandishing a big sword. If answered correctly, the person is freed. If answered incorrectly, the person is beheaded immediately. No communication between subjects is allowed, although they can hear each others' guesses.

You have a chance to meet with the subjects ahead of time - the night before this incident - to give them a strategy that will save the most number of lives (guaranteed, not a probability or expected outcome).

I assume the question is "what is the strategy that guarantees the maximum number of lives saved"? This has been asked before here, but the answer is:
Each person in line counts the number of blue hats they see in front of them. God forbid any of them are colorblind. The last person in line (the first person to be chosen) says "blue" if the number he counts is odd, and "red" if it's even. He has a 50% chance to survive. Following this, each person can deduce the color of their hat. If the 2nd to last person's count was odd, and the last person's count was also odd, he knows he has a red hat. If the last person's count was even, then he knows he has a blue hat. And so forth down the line.

DaveE
 
  • #184


davee123 said:
Quick algebra yields that the answer is the 2nd digit of the answer to question 1 times the 4th digit of question 1.
[/SPOILER]DaveE
You sure about that? I don't have the answer, but even I know there's more to the answer than meets the eye.
The more painters, the less time it will take. i.e. <10.
 
  • #185


davee123 said:
I already found 2 solutions.
DaveE

What are they?... I don't think you have.
 
  • #186


DaveC426913 said:
You sure about that? I don't have the answer, but even I know there's more to the answer than meets the eye.

How so? That is, what's the more? I got an answer that works using simple algebra-- why ought I doubt it?

Georgepowell said:
What are they?... I don't think you have.

Well, I went outside the box. I was mildly annoyed that the question implied (but didn't stipulate) that it was "a positive integer less than one million". So I found the solution that I think was implied, then found another one assuming it was "a number less than one million".

[edit]Admittedly, in thinking about it, one could argue that the implications of placing a 1 before or after a number imply different mathematical functions-- in which case I could arguably have 0, 1, or 2 alternate solutions. And I'm not talking about using alternate bases or anything, although that could make for quite a large number of alternate solutions.[/edit]

DaveE
 
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  • #187


davee123 said:
Admittedly, in thinking about it, one could argue that the implications of placing a 1 before or after a number imply different mathematical functions-- in which case I could arguably have 0, 1, or 2 alternate solutions. And I'm not talking about using alternate bases or anything, although that could make for quite a large number of alternate solutions.

DaveE
Here is how I did it
10x + 1 = 3(x+10^y) where y is an integer between 1 and 6, and x is an integer between 1 and a million... when y = 5, x = 42857

another solution that is too large (bigger than 1,000,000) is 4,285,714,286 ! I don't want to find the next highest one...
 
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  • #188


davee123 said:
I'm not sure I understand what the trick is here. Maximizing the sum is as easy as maximizing each term within the sum. Each term is a square of a digit of x, which means maximizing each digit's square. Maximizing a square of a digit simply means maximizing that digit. Hence, 999 = x, making f(x) = 9^2 + 9^2 + 9^2 = 243.

DaveE

Given any three-digit number, x, define f(x) to be
x minus the sum of the squares of the digits of x
What is the maximum possible value of f(x)?

*[the '-' sign means 'minus' in this context, sorry for being unclear, I have changed it now.]

so if x = 999, then f(x) would equal 999-243 = 756
if x = 990 then f(x) would equal 999-162 = 828 (higher, but I don't think is the highest)

now you see the problem is a little more difficult...
 
  • #189


Georgepowell said:
*[the '-' sign means 'minus' in this context, sorry for being unclear, I have changed it now.]

so if x = 999, then f(x) would equal 999-243 = 756
if x = 990 then f(x) would equal 999-162 = 828 (higher, but I don't think is the highest)

now you see the problem is a little more difficult...

Ahhh, that makes more sense then.

f(950) = f(951) = 844

[edit]For the record on #1:
I found 42857 as the answer, but also -42857 and -3/2 arguably work. You could argue that if the number is "-42857" that adding a 1 *before* the number would mean "1-42857" instead of "-142857", but if the latter is accepted, then it's also a solution. -3/2 could (again arguably) work since 1-3/2 is -1/2, and -3/2 with a "1" after it may imply a multiplication by 1 (obviously if it implies an addition of 1, then it's unchanged from 1-3/2). I haven't checked, but in typing out this response, it's possible that adding a 1 after a fraction, when written in a text editor might imply a denominator that's ten times as much, plus 1. There could be an answer there, too. Hm... I didn't even try complex numbers, but that's another thought.
[/edit]

DaveE
 
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  • #190


davee123 said:
How so? That is, what's the more? I got an answer that works using simple algebra-- why ought I doubt it?
Again: is your answer less than 10? It should be. If not, you've fallen for the deception.
 
  • #191


[edit]wrapped spoilers[/edit]
DaveC426913 said:
Again: is your answer less than 10? It should be. If not, you've fallen for the deception.

You think it should be less than 10 hours? Why? Clearly it should be less than 12, because that's how long it took Adam and Ben to do a whole house-- so unless Colin is actively UNPAINTING the house, the answer must be less than 12. But where are you getting 10 from?

Let:
A = the number of houses Adam can paint in an hour
B = the number of houses Ben can paint in an hour
C = the number of houses Colin can paint in an hour

A*12 + B*12 = 1
A*15 + C*15 = 1
B*20 + C*20 = 1

Solve for A, B, and C. Next, you want to know how many hours (H) it'll take for all 3 of them to paint 1 house:

A*H + B*H + C*H = 1

Solve for H.

Did I miss something?

DaveE
 
  • #192


davee123 said:
I found 42857 as the answer, but also -42857 and -3/2 arguably work. You could argue that if the number is "-42857" that adding a 1 *before* the number would mean "1-42857" instead of "-142857", but if the latter is accepted, then it's also a solution. -3/2 could (again arguably) work since 1-3/2 is -1/2, and -3/2 with a "1" after it may imply a multiplication by 1 (obviously if it implies an addition of 1, then it's unchanged from 1-3/2). I haven't checked, but in typing out this response, it's possible that adding a 1 after a fraction, when written in a text editor might imply a denominator that's ten times as much, plus 1. There could be an answer there, too. Hm... I didn't even try complex numbers, but that's another thought.

DaveE

I think your looking into it a bit too deeply :p

2: If Adam and Ben worked together to paint a house they would take 12 hours. Adam and Colin as a team would take 15 hours to paint the house and Ben and Colin as a pair would take 20 hours.
Assuming that the rate at which each painter works is not affected by whom he works with, how long would it take to paint the house if they all worked together?


I got 10 hours exactly, can anyone confirm this?
 
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  • #193


Georgepowell said:
I think your looking into it a bit too deeply :p

I agree.

Often times, people write incomplete or malformed questions. Particularly in this forum, people post things like word problems with huge gaping holes, and then claim that solutions presented are wrong simply because answerers are able to dodge the exact wording of the problem. As a computer programmer, I'm frequently reminded of the unexpected boundaries of inputs, so I'm perhaps a bit more anal than most.

Sometimes (more frequently in this forum than others online) it's because English isn't the person's first language. So many times, I have to be forgiving because the translation is imperfect, and I can't tell with what accuracy the person intended to write the problem.

But honestly, the real temptation was the fact that you stipulated with seeming assurity that "All the questions only have one solution". That just beckoned me-- something like a dare. "I dare you to find an error with my problems!" If it weren't for that baiting me, I probably would've ignored the post all together, since I think that all the problems you posted (other than the 3rd one) have been posted here before.

So I looked at the first problem, and almost immediately concluded that "a number less than 1 million" would almost assuredly provide for *TWO* solutions, the answer you expected and the negative counterpart of the answer you expected. Immediately, I started thinking about other interpretations as well, like decimals (although I believe I logically eliminated that possibility), fractions, bases, and so forth.

Anyway, with one error in hand, and a lack of understanding of the 3rd problem, I decided to go ahead and post. Actually, I should've pointed out some errors in your wording on problem #4 as well, since you didn't say that the king will ask the question to each person in the line starting from the back and working up to the front. You only said that the last person gets asked the question. You also said "guaranteed, not a probability or expected outcome", which is wrong. The last person's chance of survival are 50/50, no matter what. Hence, if the number of subjects is 1, the answer is necessarily a probability. And if the number of subjects is 2, then there are multiple strategies that result in the same survival rate, each of which in turn has a 50% chance of happening (either 1 person is killed, or 0 are killed).

And to go off on a tangent, when this (#4) has been asked before, very frequently people suggest that the strategy should be some alternate form of communication-- something like "if the next person's hat is red, you state the color of your hat quickly in a squeaky voice, and if it's blue, you state the color of your hat slowly in a deep voice". Which then means that you (as the asker of the question) have to say "no, you can't say 'red' or 'blue' any differently". And that sometimes continues for a dozen posts or so, with people trying to find loopholes. Instead, if you plan on asking it again elsewhere, you can avoid this by suggesting that each person must point to the color hat that they believe they were given, which the king will dutifully announce, such that the next people in line can hear.

Anyway, remember to clearly spell out your assumptions when writing word problems!

DaveE
 
  • #194


davee123 said:
[edit]wrapped spoilers[/edit]


You think it should be less than 10 hours? Why? Clearly it should be less than 12

DaveE

OK, well that's what I was getting at. I just got a little overzealous. :redface:
 
  • #195


Georgepowell said:
[edit]spoiler tags corrected[/edit]
another solution that is too large (bigger than 1,000,000) is 4,285,714,286 ! I don't want to find the next highest one...

That's not correct-- clearly any answer must end in a 7, since that's the only digit that, when multiplied by 3, will give you a product whose last digit is 1. In fact, it's pretty easy to find the next largest number, it's 42857142857. And the next one after that will be 42857142857142857, followed by 42857142857142857142857. The tricky part is finding that first pattern. Once you've got it, the rest of the solutions unfold easily.

DaveE
 
  • #196


davee123 said:
That's not correct-- clearly any answer must end in a 7, since that's the only digit that, when multiplied by 3, will give you a product whose last digit is 1. In fact, it's pretty easy to find the next largest number, it's 42857142857. And the next one after that will be 42857142857142857, followed by 42857142857142857142857. The tricky part is finding that first pattern. Once you've got it, the rest of the solutions unfold easily.

DaveE

sorry that was just a miss-type, you are right. I did find the next answer like this:

I found it by dividing 2999... etc. by 7, I kept adding another 9 until I found another multiple of 7, 42857142857*7 = 299,999,999,999, and 42857142857142857142857*7 = 29999 bla bla bla!
 
  • #197


davee123 said:
I agree.

Often times, people write incomplete or malformed questions. Particularly in this forum, people post things like word problems with huge gaping holes, and then claim that solutions presented are wrong simply because answerers are able to dodge the exact wording of the problem. As a computer programmer, I'm frequently reminded of the unexpected boundaries of inputs, so I'm perhaps a bit more anal than most.

-...-

Anyway, remember to clearly spell out your assumptions when writing word problems!

DaveE

I (partly) agree, but I did not write the questions, so I am not to blame :D

I got them from:

http://www.fmnetwork.org.uk/files/GRfin0708.pdf
and
http://www.fmnetwork.org.uk/files/GRreg0708.pdf
and
http://answers.yahoo.com/question/i...ePCbVMPsy6IX;_ylv=3?qid=20070810141316AA4644N

The first two links are questions from a maths challenge that I was a part of (our team of four came 6th) although that was this year, and the questions where not the same.
 
  • #198


The easiest way to solve it (I think) is by taking it one step at a time in reverse. I can't use pre-formated text AND spoilers at the same time, so bearing with that:

1abcdef
x3
abcdef1

Since the ones place of f*3 is 1, that means f=7:

1abcde7
x3
abcde71

Now, since 3*7 has a tens place of 2, and the ones place of 3*e + 2 = 7, we know that 3*e's ones place is a 5. Hence, e=5:

1abcd57
x3
abcd571

Same process, 3*5 has a tens place of 1, and the ones place of 3*d + 1 = 5, which means that 3*d's ones place is a 4. Hence, d=8.

1abc857
x3
abc8571

Next, again, 3*8 has a tens place of 2, and ones place of 3*c+2 = 8, therefore 3*c ends in a 6, making c=2.

1ab2857
x3
ab28571

Now, one more time, 3*2 has a tens place of 0, so 3*b+0 = 2, which means b=4.

1a42857
x3
a428571

And FINALLY, 3*4 has a tens place of 1, which means 3*a+1 = 4. So a=1. So since the 1st digit must be a 1, we can choose to stop there (at b), or keep going. However, since we want the smallest value possible, we use 42857 rather than 42857142857, which would be the next number we'd hit if we continued.

[edit]
Georgepowell said:
I (partly) agree, but I did not write the questions, so I am not to blame :D

I disagree that you're not to blame, although as stated earlier, the blame is small. You posted the problem, therefore you have a responsibility to ensure that the problem is correctly stated, regardless of how the problem was relayed to you. Spreading a faulty problem doesn't absolve you of responsibility, it just means that someone else is just as at fault as you are. But again, this is a pretty minor transgression. It's not like you're publishing it in a math textbook or something-- it's a forum, after all. But I still say the onus is on you as a poster to ensure the accuracy of problems presented.
[/edit]

DaveE
 
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  • #199


new puzzle, I just made it up and i don't know the correct answer, if there is one...

I have 2, 3 digit numbers, a and b. what are the two values for a and b so that (a/b)'s decimal expansion is the longest? (not including reccuring decimals like 333/999 = 0.33333 etc.)

ie. if a and b where one digit numbers, then it would be something like 1/7 = 0.142857 blablabla
 
  • #200


Georgepowell said:
I have 2, 3 digit numbers, a and b. what are the two values for a and b so that (a/b)'s decimal expansion is the longest? (not including reccuring decimals like 333/999 = 0.33333 etc.)

Hmm... Effectively, you want a denominator whose only factors are 2 and 5 (which can occur multiple times). Otherwise, you get something like 1/7, which is a repeating decimal:

0.1428571428571428571428571428571428571428571428...

Georgepowell said:
if a and b where one digit numbers, then it would be something like 1/7 = 0.142857 blablabla

If they're 1-digit integers (not decimals, since "3.93" is a 3-digit number and ".3" is similarly a 1-digit number, and I assume you mean integers, although you should probably specify that), then the viable answers would be:

1/8 = 0.125
3/8 = 0.375
5/8 = 0.625
7/8 = 0.875

If we include 1-digit decimal values like ".4" or ".9", then we can get an extra digit of extension:

.1/8 = 0.0125
.3/8 = 0.0375
.5/8 = 0.0625
.7/8 = 0.0875

So my preliminary guess will be:

n/512 where n is not divisible by 2.

For example:
371/512 = 0.724609375

My offhand guess is that you want to cram in as many factors as you can to the denominator, and since 2 is smaller than 5, you just find the highest power of 2 such that it's an integer less than 1000, or 512. The numerator shouldn't really matter-- it might serve to *reduce* the number of digits in the result (because it may be a reducible fraction), so using a numerator of 1 ought to be just as effective or more effective than any other numerator. I may need to ponder on this more to make sure, but I think that's correct.

[edit]
Verified. n/512 (n not divisible by 2) is the longest length decimal with a non-repeating decimal portion (assuming "0000000000..." counts as non-repeating).

And if you meant the longest repeating portion of a decimal, then it's n/983 where n is not divisible by 983. The repeating decimal portion of 1/983 is 982 digits long:

0010172939979654120040691759918616480162767039674465920651068158697863682604272634791454730417090539165818921668362156663275686673448626653102746693794506612410986775178026449643947100712105798575788402848423194303153611393692777212614445574771108850457782299084435401831129196337741607324516785350966429298067141403865717192268565615462868769074262461851475076297049847405900305188199389623601220752797558494404883011190233977619532044760935910478128179043743641912512716174974567650050864699898270600203458799593082400813835198372329603255340793489318413021363173957273652085452695829094608341810783316378433367243133265513733468972533062054933875890132248219735503560528992878942014242115971515768056968463886063072227873855544252288911495422177009155645981688708036622583926754832146490335707019328585961342828077314343845371312309257375381485249237029501525940996948118006103763987792472024415055951169888097660223804679552390640895218718209562563580874872838250254323499491353

[/edit]

DaveE
 
Last edited:

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