Can a pendulum have a constant speed in vertical circular motion?

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SUMMARY

A pendulum swinging in a vertical circle cannot maintain a constant speed throughout its motion due to the conversion of kinetic energy (KE) to potential energy (PE) as it rises. As the pendulum ascends, its height increases, resulting in an increase in potential energy and a corresponding decrease in kinetic energy, which leads to a reduction in linear speed. The relationship between linear speed (v), angular velocity (ω), and radius (r) is defined by the equation v = ωr, indicating that if v decreases while r remains constant, angular velocity (ω) must also decrease.

PREREQUISITES
  • Understanding of kinetic energy (KE) and potential energy (PE) concepts
  • Familiarity with the equations of motion for pendulums
  • Knowledge of angular velocity and its relationship to linear speed
  • Basic grasp of conservation of mechanical energy principles
NEXT STEPS
  • Study the conservation of mechanical energy in different systems
  • Explore the dynamics of pendulum motion in various gravitational fields
  • Learn about the effects of damping on pendulum motion
  • Investigate the mathematical modeling of circular motion in physics
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of energy conservation and motion dynamics in pendulums.

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Homework Statement



Can a pendulum that swings in a vertical circle have a constant speed throughout its motion?
How can I explain this phenomenon using angular velocity? Is there any instance when such case happen?

Homework Equations



1/2mv2 = mgh
velocity= radius X angular velocity

The Attempt at a Solution



Nope. When the pendulum swings up some of the kinetic energy is being converted to potential energy and thus the speed of the pendulum decreases. OR
The angular velocity of the pendulum decreases(why?)
 
Last edited:
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You have already established that the linear speed decreases because the kinetic energy decreases. If v decreases and r stays the same, what happens to the angular velocity? Look at your second equation. By the way, kinetic energy has v2 in it, not just v.
 
The velocity decreases because at it comes near the top of the circle, the radius(of the vertical circle)decreases and since angular velocity is constant and depends only on the time it takes for one revolution. Thx! ^_^ Lol sry 4 the equation mistake.
 
Let's take it from the top.

KE = (1/2)mv2; PE = mgh

The total mechanical energy is constant, KE + PE = Constant

Therefore when the pendulum goes higher, two things happen PE increases because h increases and KE decreases to keep the sum KE + PE constant.

But if KE decreases, v must also decrease.

Now in terms of angular velocity ω, v = ω r.

Here, r is the length of the pendulum. This stays constant as the pendulum swings back and forth.

So ...

Looking at v = ω r, if v decreases and r stays the same, what happens to ω?
 
Lol ok the angular velocity decreases. Sry because I confuse it w/horizontal circular motion.:biggrin:
 

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