Can a pendulum have a constant speed in vertical circular motion?

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Homework Help Overview

The discussion revolves around whether a pendulum swinging in a vertical circle can maintain a constant speed throughout its motion. Participants explore the relationship between kinetic energy, potential energy, and angular velocity in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the conversion of kinetic energy to potential energy as the pendulum rises, leading to a decrease in speed. Questions are raised about the implications of this on angular velocity and the relationship between linear speed and radius.

Discussion Status

The discussion is active, with participants providing insights into the mechanics of energy conservation and the effects on angular velocity. There is a focus on clarifying misunderstandings regarding the equations involved and the behavior of the pendulum's motion.

Contextual Notes

Participants note the importance of understanding the conservation of mechanical energy in the context of the pendulum's motion and the implications of changing kinetic and potential energy on speed and angular velocity.

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Homework Statement



Can a pendulum that swings in a vertical circle have a constant speed throughout its motion?
How can I explain this phenomenon using angular velocity? Is there any instance when such case happen?

Homework Equations



1/2mv2 = mgh
velocity= radius X angular velocity

The Attempt at a Solution



Nope. When the pendulum swings up some of the kinetic energy is being converted to potential energy and thus the speed of the pendulum decreases. OR
The angular velocity of the pendulum decreases(why?)
 
Last edited:
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You have already established that the linear speed decreases because the kinetic energy decreases. If v decreases and r stays the same, what happens to the angular velocity? Look at your second equation. By the way, kinetic energy has v2 in it, not just v.
 
The velocity decreases because at it comes near the top of the circle, the radius(of the vertical circle)decreases and since angular velocity is constant and depends only on the time it takes for one revolution. Thx! ^_^ Lol sry 4 the equation mistake.
 
Let's take it from the top.

KE = (1/2)mv2; PE = mgh

The total mechanical energy is constant, KE + PE = Constant

Therefore when the pendulum goes higher, two things happen PE increases because h increases and KE decreases to keep the sum KE + PE constant.

But if KE decreases, v must also decrease.

Now in terms of angular velocity ω, v = ω r.

Here, r is the length of the pendulum. This stays constant as the pendulum swings back and forth.

So ...

Looking at v = ω r, if v decreases and r stays the same, what happens to ω?
 
Lol ok the angular velocity decreases. Sry because I confuse it w/horizontal circular motion.:biggrin:
 

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