- #31
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mfb said:
OOPS. My bad. Thanks for that correction. I can add, but I can't multiply
Hm ... I don't follow. How does our view of them freeze? Wouldn't they just fade into darkness with greater and greater redshift?
Can an Object Falling in Infinite Gravity Break the Speed of Light?
- Thread starter henrywang
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An object falling in a gravitational field with an infinitely long radius cannot exceed the speed of light due to the principles of special relativity, which dictate that nothing can travel faster than light (c). Even with infinite acceleration, the energy required to reach light speed becomes infinite, making it impossible to achieve. The discussion emphasizes that "why" questions are not typically addressed by physics, which focuses on "how" things work. The Higgs mechanism, which provides mass to particles, does not change the fundamental limit imposed by the speed of light. Ultimately, the consensus is that no material object or energy can surpass this universal speed limit.
OOPS. My bad. Thanks for that correction. I can add, but I can't multiply
Hm ... I don't follow. How does our view of them freeze? Wouldn't they just fade into darkness with greater and greater redshift?
- #32
ExecNight
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I would expect them to freeze and redshift into darkness because;
Well for conservation of information i would expect them to act like an object falling into the black holes event horizon. Otherwise, that would raise many questions. Like Stephen Hawking did back then
Well for conservation of information i would expect them to act like an object falling into the black holes event horizon. Otherwise, that would raise many questions. Like Stephen Hawking did back then
- #33
mfb
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Into darkness, but also into slower evolution (as seen by us) due to the redshift. The effect is very similar to objects falling into black holes (as seen by outside observers), just on a completely different timescale.phinds said:
- #34
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mfb said:
OK, that I understand. I think the fading to darkness would occur before the "freezing" got too severe, but I guess you could say that depends on the sensitivity of the instruments "seeing" the objects.
- #35
xox
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henrywang said:
No, the coordinate speed of a test probe falling from infinity is:
v=c(1-\frac{r_s}{r}) \sqrt{\frac{r_s}{r}} for r>r_s
where r_s is the Schwarzschild radius of the "attracting" gravitational mass and r is the radial Schwarzschild coordinate. So, v<c for all r>r_s.
If the test probe is dropped from r_0 the formula becomes:
v=c(1-\frac{r_s}{r}) \sqrt{\frac{r_s}{r}-\frac{r_s}{r_0}} for r_0>r>r_s
For light, the coordinate speed is:
v=c(1-\frac{r_s}{r})
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