Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Can anyone help my start this problem?

  1. Nov 28, 2005 #1
    A 0.150-m-radius grinding wheel, starting at rest, develops an angular speed of 12.0 rad/s in a time interval of 4.00 s. What is the centripetal acceleration of a point 0.100 m from the center when the wheel is moving at an angular speed of 12.0 rad/s?
  2. jcsd
  3. Nov 28, 2005 #2

    Tom Mattson

    User Avatar
    Staff Emeritus
    Science Advisor
    Gold Member

    First state the formula for centripetal acceleration. Then look for those quantities in the problem statement.

    Give it a try. If you get stuck then post what you have done and where you got stuck. But you must show an attempt at the problem in order to receive help here.
  4. Nov 28, 2005 #3
    Ac= v^2 / r

    12^2 / .100 which I got 1440. and the answer is 14.4
  5. Nov 28, 2005 #4


    User Avatar
    Homework Helper

    It is true that centripetal acceleration = v^2/r, where v is the tangential velocity.

    However, the 12 you are using is angular velocity. You may convert this [tex]\omega = \frac{v}{r}[/tex] or use the alternative formula: [tex]a_c = \omega^2r[/tex]
  6. Nov 28, 2005 #5
    :blushing: ooh....thanks for the help :smile:
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook