Can anyone help my start this problem?

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In summary, the problem involves finding the centripetal acceleration of a point on a grinding wheel, given its radius, angular velocity, and time interval. Using the formula for centripetal acceleration, we can solve for the acceleration and get a value of 14.4 m/s^2.
  • #1
physics_ash82
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A 0.150-m-radius grinding wheel, starting at rest, develops an angular speed of 12.0 rad/s in a time interval of 4.00 s. What is the centripetal acceleration of a point 0.100 m from the center when the wheel is moving at an angular speed of 12.0 rad/s?
 
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  • #2
First state the formula for centripetal acceleration. Then look for those quantities in the problem statement.

Give it a try. If you get stuck then post what you have done and where you got stuck. But you must show an attempt at the problem in order to receive help here.
 
  • #3
Ac= v^2 / r

12^2 / .100 which I got 1440. and the answer is 14.4
 
  • #4
It is true that centripetal acceleration = v^2/r, where v is the tangential velocity.

However, the 12 you are using is angular velocity. You may convert this [tex]\omega = \frac{v}{r}[/tex] or use the alternative formula: [tex]a_c = \omega^2r[/tex]
 
  • #5
:blushing: ooh...thanks for the help :smile:
 

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