Can anyone help thermodynamics specific heat

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foranlogan2
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Explaining your reasoning, show that the ratio of the specifc heat is

CP/CV = (DP/DV)s / (DP/DV)t

hint :use TDS EQUATIONS

I have used tds equation 3 and tds equation 1 and equated them,but i am stuck because i get to an equation like


(CP/CV-1)(DT/DV)p = T(DP/DT)v and just do not know how to get to the ratio

how i used the wrong equations or is it my maths skills,please help:bugeye:
 
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We don't know what these equations are. What are TDS equations 1 and 3.
 
CVDT + T(DP/DT)vDV = TDS 1

CPDT - T(DV/DT)pDP = TDS 2


CV(DT/DP)vDP + CP(DT/DV)pDV = TDS 3