Solving for x in terms of y: Methods and Alternatives

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SUMMARY

The discussion centers on solving quadratic equations for x in terms of y, specifically through the method of "completing the square." The quadratic formula is derived from this method, which allows for the transformation of the standard form ax² + bx + c = 0 into a solvable format. The key transformation involves rewriting the equation as (x + b/2a)² = (b/2a)² - c/a, leading to the final solution x = (-b ± √(b² - 4ac)) / 2a. This method is particularly useful when alternative approaches to the quadratic formula are sought.

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Can Anyone Understand this?

See the attachment///
Can Anyone Understand this?
I mean what metod has he followed to solve this equation for x in terms of y , does someone have any method to solve it other than the quadratic formula?/
 

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It's called "completing the square", and it's where the quadratic formula comes from. Remember, if I have:
x^2+2ax + a^2 = 0 , I can write it as
(x+a)^2 = 0 .
So if I have
ax^2+bx+c = 0
I can write it as:
x^2+\frac{b}{a}x+(\frac{b}{2a})^2 =(\frac{b}{2a})^2-\frac{c}{a}
where I have added (\frac{b}{2a})^2 to both sides. This is also:
(x+\frac{b}{2a})^2 = (\frac{b}{2a})^2-\frac{c}{a}
or:
(x+\frac{b}{2a}) =\pm\sqrt{(\frac{b}{2a})^2-\frac{c}{a}}
or:
x =-\frac{b}{2a}\pm\sqrt{(\frac{b}{2a})^2-\frac{c}{a}}
or:
x =\frac{-b\pm\sqrt{b^2-4ac}}{2a}

This is what they have done, but with \frac{7y+13}{24} playing the role of \frac{b}{2a}
 


Thanks friend
 

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