Can Derivative Methods Determine the Correct Angle in Physics Problems?

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SUMMARY

The discussion centers on the application of derivative methods to determine the correct angle in physics problems, specifically regarding the calculation of moments. Participants emphasize the importance of specifying units, such as using "1500sin(θ) Nm" for clarity. It is confirmed that taking the point of action of a force along its line simplifies calculations, particularly when the horizontal component has no moment about the pivot point O. The initial confusion regarding the terminology of "momentum" instead of "moment" is also addressed.

PREREQUISITES
  • Understanding of basic physics concepts, particularly moments and forces.
  • Familiarity with trigonometric functions, specifically sine functions.
  • Knowledge of calculus, particularly derivative methods.
  • Ability to apply unit measurements in physics calculations.
NEXT STEPS
  • Study the application of derivatives in physics problems involving angles.
  • Learn about calculating moments in static equilibrium scenarios.
  • Research the significance of specifying units in physics equations.
  • Explore the differences between momentum and moment in physics terminology.
USEFUL FOR

Students and educators in physics, engineers working on mechanics problems, and anyone interested in applying calculus to physical scenarios involving angles and moments.

Tapias5000
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Homework Statement
Determine the moment of the force with respect to point O as a function of θ . for what value of θ in the range between 0° and 180° is the moment at its maximum? what is the value of the moment in this case?
Relevant Equations
Mo= R x F
This is the image of the problem:
Captura.PNG

I tried to solve it and I got the following is it correct?

1631573856591.png

derive and equal to 0 because it is between an angle of 0 and 180° is this statement correct?
 
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Looks fine, though you should specify units everywhere, e.g. ##1500\sin(\theta)Nm##.

You can take the point of action of a force as anywhere along its line of action, so it is simpler to consider the force acting at the centre of the arc. The horizontal component then has no moment about O, and you can write the answer down immediately.

Btw, you put "momentum" in the title instead of "moment".
 
haruspex said:
Looks fine, though you should specify units everywhere, e.g. ##1500\sin(\theta)Nm##.

You can take the point of action of a force as anywhere along its line of action, so it is simpler to consider the force acting at the centre of the arc. The horizontal component then has no moment about O, and you can write the answer down immediately.

Btw, you put "momentum" in the title instead of "moment".
ok, but I still need to find the angle, is the statement I said correct to find it?
 
Tapias5000 said:
ok, but I still need to find the angle, is the statement I said correct to find it?
Yes.
 
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