- #1
brendan
- 65
- 0
Hi all,
I am trying to work out a series expansion for ln ((x+1)/(x-1)).
I have got the series expansion for ln(x+1) ie x- (x^2/2) + (x^3/3) - (x^4/4) ...
and for ln(x-1) -x- (x^2/2) - (x^3/3) - (x^4/4) ...
Can I tie these two together to get the series for ln ((x+1)/(x-1)).
Or do I treat this as a new series.
regards
Brendan
I am trying to work out a series expansion for ln ((x+1)/(x-1)).
I have got the series expansion for ln(x+1) ie x- (x^2/2) + (x^3/3) - (x^4/4) ...
and for ln(x-1) -x- (x^2/2) - (x^3/3) - (x^4/4) ...
Can I tie these two together to get the series for ln ((x+1)/(x-1)).
Or do I treat this as a new series.
regards
Brendan