Can I Make a Sequence for this Data to the nth Term?

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SUMMARY

The discussion focuses on formulating a sequence for a given set of equations related to doses and their respective terms. The equations provided are: y(1) = De^(0*12*k)/(1-e^(0*12*k)), y(2) = D*e^(1*12*k)/(1-e^(12k)) + De^(0*12*k), and y(3) = D*e^(2*12*k)/(1-e^(12k)) + De^(1*12*k) + De^(0*12*k). The conclusion emphasizes that while the first term presents a unique challenge, subsequent terms can be expressed in a general form as y(n) = D*e^((n-1)*12*k)/(1-e^(12*k)) + Σ(De^(i*12*k)) for i from 0 to n-1.

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Homework Statement


I have a problem where I need to know if I can make a sequence for this data to the nth term. The first term, however, isn't common. Is there any way to somehow make it a sequence?
At dose 1 y(1)=De^(0*12*k)/(1-e^(0*12*k))
at dose 2 y(2)=D*e^(1*12*k)/(1-e^(12k)) + De^(0*12*k)
at dose 3 y(3)=D*e^(2*12*k)/(1-e^(12k)) +De^(1*12k)+De^(0*12*k)
so it should continue so that De^(12nk)+D(1+e^(1*12*k)+e^(2*12*k)+...+e^(nkt))
Is there any way i can make it look somewhat like a sequence or an nth term equation?
 
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Well, of course, it is a sequence but you seem to be asking if you can write a formula for the "nth" value. If it is only the first term that is a problem, write y(1)= your first formula, then "if n> 1, y(n)= ".
 

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