Can I Represent ln(1+x) as a Power Series?

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SUMMARY

The power series representation of the natural logarithm function ln(1+x) is confirmed to be equivalent in two forms: ln(1+x) = ∑_{n=0}^{∞} (-1)^n n! x^{n+1} / (n+1)! and ln(1+x) = ∑_{n=0}^{∞} (-1)^n x^{n+1} / (n+1). The equivalence is established through the simplification of factorial terms, demonstrating that both series converge to the same function. This discussion clarifies the mathematical relationship between these two representations of ln(1+x>.

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  • Concept of natural logarithms and their properties
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donutmax
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hi!

are the following power series equivalent?

ln(1+x)=\sum_{n=0}^{\infty} \frac{(-1)^n n! x^{n+1}}{(n+1)!}
=\sum_{n=0}^{\infty} \frac{(-1)^n x^{n+1}}{n+1}
 
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Yes.
 
\frac{(-1)^n n! x^{n+1}}{(n+1)!}=\frac{(-1)^n x^{n+1}}{(n+1)!/n!}=\frac{(-1)^n x^{n+1}}{(n+1)}
 
CRGreathouse said:
\frac{(-1)^n n! x^{n+1}}{(n+1)!}=\frac{(-1)^n x^{n+1}}{(n+1)!/n!}=\frac{(-1)^n x^{n+1}}{(n+1)}

He's everywhere I want to be!
 

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