Can L'Hopital's Rule Solve tan(pi*x/2)ln(x) as x Approaches 1?

[magnifik]

Homework Statement

Find the limit as x goes to 1 of tan(pi*x/2)lnx

Homework Equations

using l'hospital's, lim f'(x)/g'(x)=answer

The Attempt at a Solution

i tried integrating by making the tangent part squared so i can divide by the tangent part, but i keep getting stuck. i think the answer is either 1 or infinity.

help please? thanks

 

[Dick]

I really don't know how you are trying to do the problem. l'Hopital's rule doesn't tell you to integrate anything. Write it as ln(x)/cot(pi*x/2). Now it's a 0/0 form. Now differentiate numerator and denominator like l'Hopital says.

 

[magnifik]

woops i meant taking the derivative

 

[Mark44]

Integrating has nothing to do with this problem. Try rewriting your limit as
$$\lim_{x \to 1}\frac{ln(x)}{cot(x*\pi/2)}$$

Now you have something you can use L'Hopital's Rule on.