- #1
Philip17
- 4
- 0
Consider a partially filled bottle of water. When it's tipped over and rotating about its pivot point where its edge touches the ground, it has an angular acceleration. Assuming the liquid is not viscous at all, so flows perfectly, at a given instant can it be considered to have a moment of inertia equal to that of a rigid body of the same shape? Could its angular acceleration thus be calculated using this moment of inertia and its instantaneous center of mass? This would mean that its moment of inertia changes as it falls.
Thank you :)
Thank you :)