Can magnetic field exist without electric field?

Click For Summary
The discussion centers on the relationship between electric and magnetic fields, particularly whether a magnetic field can exist independently of an electric field. Participants note that while electric fields can exist without magnetic fields, the reverse is more complex. It is argued that magnetic fields can be present in regions where electric fields are negligible, such as in permanent magnets, where the electric fields of electrons are effectively canceled by protons. The conversation also touches on the concept of reference frames in electromagnetism, suggesting that under certain conditions, it is possible to observe a magnetic field without an accompanying electric field. Ultimately, the consensus acknowledges that while magnetic and electric fields are interconnected, specific scenarios allow for the existence of one without the other.
  • #31
Classically you can certainly have an electric field without a magnetic field or a magnetic field without an electric field. On the quantum level, since all fundamental charged particles also have spin you cannot have either without the other.

In either case the answer to the question is the same for the magnetic field as it is for the electric field, but the answer differs between classical and quantum EM.
 
Physics news on Phys.org
  • #32
DaleSpam said:
Classically you can certainly have an electric field without a magnetic field or a magnetic field without an electric field. On the quantum level, since all fundamental charged particles also have spin you cannot have either without the other.

It is possible also for neutral particles to have a non-zero magnetic moment. Of course, if you are moving relative to such a particle an electric field still appears ...

Does it really make sense to talk about electric and magnetic fields on the quantum level other than as a semi-classical approximation?
 
  • #33
Orodruin said:
It is possible also for neutral particles to have a non-zero magnetic moment. Of course, if you are moving relative to such a particle an electric field still appears ...

I don't think we would call them neutrons if they could acquire electric fields every time something is moving somewhere.
 
  • #34
Just as moving charges give you magnetic fields, anything giving rise to a magnetic field that moves is going to give you an electric one. This is due to how the electromagnetic field transforms under Lorentz transformations. The divergence of the electric field from the moving magnetic source would still be zero and so also the charge density.
 
  • #35
cabraham said:
Under static conditions, either can exist w/o the other. A superconducting loop w/ a steady dc current has magnetic field, but no electric field. The counterpart of this setup is a charged capacitor open circuited, as there is an electric field w/o a magnetic field.

Again these are static conditions, i.e. not changing with respect to time. Under dynamic conditions, i.e. changing wrt time, neither can exist w/o the other. If one field is time-changing, the other must be non-zero.

Claude

What about transformer cores? the magnetic field oscillates at 50 hz but there's no electric field in a metal. There's eddy currents but no electric field, or am I missing something?
 
  • #36
Thierry said:
What about transformer cores? the magnetic field oscillates at 50 hz but there's no electric field in a metal. There's eddy currents but no electric field, or am I missing something?
Yes there certainly are eddy currents in the core metal. But why would you conclude that there is 0 electric field? Core metal is conductive with value ##\sigma##, eddy current density has value ##J##, and remembering Ohm's law in 3 dimensions: ##J=\sigma E##, so that ##E=J/\sigma##.

Does that help? Best regards.

Claude
 
  • #37
Thierry said:
there's no electric field in a metal

...under electrostatic conditions.
 
  • #38
cabraham said:
Yes there certainly are eddy currents in the core metal. But why would you conclude that there is 0 electric field? Core metal is conductive with value ##\sigma##, eddy current density has value ##J##, and remembering Ohm's law in 3 dimensions: ##J=\sigma E##, so that ##E=J/\sigma##.

Does that help? Best regards.

Claude
ah yes, it does. Thanks!
 
  • #39
jtbell said:
...under electrostatic conditions.
I see. of course, thanks!
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
10
Views
2K
Replies
11
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 22 ·
Replies
22
Views
5K
  • · Replies 9 ·
Replies
9
Views
3K