Can Mary Minimize Her Costs and Make a Profit?

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SUMMARY

Mary Jane aims to minimize her costs while achieving a value added of $18,000 from her herb production, modeled by the production function Q = 3(K*L)^0.5. The optimal values of capital (K) and labor (L) must be determined by equating the isoquant's slope, -L/K, to the relative price of inputs, which is the ratio of labor cost ($7.20/hour) to capital rental cost (0.20). To minimize costs effectively, Mary must solve the total cost function T = R*K + C*L under the constraint of achieving the desired output level.

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  • Understanding of production functions and isoquants
  • Knowledge of cost minimization techniques in economics
  • Familiarity with the concepts of opportunity cost and rental costs
  • Ability to solve optimization problems using calculus
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  • Calculate optimal values of K and L using the given production function
  • Explore the concept of isoquants and their application in production theory
  • Learn about cost minimization strategies in microeconomics
  • Investigate the implications of opportunity cost in production decisions
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Homework Statement



Mary Jane grows herbs in her attic. The relationship between her inputs and outputs is given by the production function is Q = 3(K*L)^0.5 , where Q is value added (value of gross output less cost of electricity, fertilizer, seed, and food for a guard dog), K is the value of capital goods (lamps, sprinklers, pots, and security systems), and L is Mary’s hours of labor. The isoquants corresponding to this production function have slope -L/K . The rental cost of capital (interest rate plus depreciation rate) is 0.20. The opportunity cost of Mary’s labor is $7.20 per hour. Mary’s goal is to obtain a value added of $18,000 as cheaply as possible. a) Find the optimal values of K and L. b) Can Mary make a profit?


Homework Equations





The Attempt at a Solution


First of all, I don't understand why the function's derivative is -L/K. I know that to minimize the cost I must solve the equation -L/K = Relative Price of L & K. I think relative price of L & K is (Cost of Labour Per Hour)/(Cost of Rent Per Hour), but I don't know the price of Rent Per Hour. And if anyone could explain me the reason why cost is minimized when the isoquant's derivative equals the relative price of inputs, I'd be grateful.
 
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kristo said:

The Attempt at a Solution


First of all, I don't understand why the function's derivative is -L/K.

The isoquants are curves of constant Q. Along these curves, the variation in Q is zero, so

0 = dQ = 3 \left( \sqrt{\frac{L}{K}} dK + \sqrt{\frac{K}{L}} dL \right).

This means that at constant Q,

\frac{dL}{dK} = - \frac{L}{K} .

I know that to minimize the cost I must solve the equation -L/K = Relative Price of L & K. I think relative price of L & K is (Cost of Labour Per Hour)/(Cost of Rent Per Hour), but I don't know the price of Rent Per Hour. And if anyone could explain me the reason why cost is minimized when the isoquant's derivative equals the relative price of inputs, I'd be grateful.

Our cost of capital is R=0.20 while our opportunity cost of labor is C= $7.20/hr. Our total cost is therefore T = R K + CL. We want to minimize this subject to the condition Q= $18k. This means that we want to minimize the function. You should find the minimum yourself, it's not quite what you wrote.
 

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