Can someone explain the 3D Dirac Delta Function in Griffiths' Section 1.5.3?

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Discussion Overview

The discussion centers around the 3D Dirac Delta Function as presented in Griffiths' section 1.5.3, specifically focusing on the divergence of the vector function r/r^2 and its implications. Participants seek clarification on the derivation and physical meaning of this relationship, as well as its mathematical formulation.

Discussion Character

  • Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant suggests using the divergence theorem to show that the integral of the divergence over a volume enclosing the origin equals 4π, indicating a relationship with the Dirac delta function.
  • Another participant mentions calculating the divergence explicitly in spherical coordinates, noting that it is zero everywhere except at the origin where it becomes infinite.
  • There is a discussion about the interpretation of the equation f(𝑟)δ³(𝑟) being equivalent to the divergence of 𝑟/𝑟², with some participants expressing confusion about the notation and its implications.
  • One participant explains that the divergence being zero except at the origin suggests a relationship with a delta function, leading to the conclusion that it must be some function f(𝑟) times the delta function.
  • Another participant acknowledges understanding the explanation provided, indicating a progression in grasping the concepts discussed.

Areas of Agreement / Disagreement

Participants express varying levels of understanding regarding the mathematical formulation and physical interpretation of the Dirac delta function in this context. Some agree on the use of the divergence theorem and the behavior of the divergence, while others seek clarification on specific aspects, indicating that the discussion remains somewhat unresolved.

Contextual Notes

Participants note the divergence of the vector function is zero except at the origin, where it is infinite, but do not resolve the implications of this behavior or the exact nature of the function f(𝑟).

cordyceps
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Griffiths' section 1.5.3 states that the divergence of the vector function r/r^2 = 4*Pi*δ^3(r). Can someone show me how this is derived and what it means physically? Thanks in advance.
 
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cordyceps said:
Griffiths' section 1.5.3 states that the divergence of the vector function r/r^2 = 4*Pi*δ^3(r). Can someone show me how this is derived and what it means physically? Thanks in advance.

First, use the divergence theorem to show that \int_{\mathcal{V}}( \vec{\nabla}\cdot\frac{\hat{r}}{r^2})d\tau=4\pi for any surface enclosing the origin (use a spherical surface centered at the origin for simplicity).

Then, calculate the divergence explicitly using the formula on the inside of the front cover for divergence in spherical coords. You should find that it is zero everywhere except at the origin where it blows up (because the 1/r terms correspond to dividing by zero).

Finally, put the two together by using eq 1.98 with f(\vec{r})\delta^3(\vec{r})\equiv \vec{\nabla}\cdot\frac{\hat{r}}{r^2}

As for a physical interpretation, there really isn't one (although there are physical consequences as you'll see in chapter 2 and beyond); but there is a geometric interpretation...if you sketch the vector function \frac{\hat{r}}{r^2} (figure 1.44 in Griffiths) you'll see why there must be an infinite divergence at the origin. This is all discussed in section 1.5.1
 
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Sorry, I'm kinda slow- why does LaTeX Code: f(\\vec{r})\\delta^3(\\vec{r})\\equiv \\vec{\\nabla}\\cdot\\frac{\\hat{r}}{r^2}?
 
Can't use latex. Why does f(R)δ^3(R) = the divergence of R/r^2?
 
cordyceps said:
Can't use latex. Why does f(R)δ^3(R) = the divergence of R/r^2?

The fact that the divergence of \frac{\hat{r}}{r^2} is zero everywhere, except at the origin where it is infinite, but when integrated gives a constant, means that it must be some unknown normal function f(\vec{r}) times a delta function so, you call it f(\vec{r})\delta^3(\vec{r}) and solve for f by setting the integral (eq. 1.98) equal to the value you calculated using the diverergence theorem (4\pi)
 
Ok. I think I got it. Thanks a lot!
 

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