Can someone explain why the voltage here is zero?

Click For Summary

Discussion Overview

The discussion revolves around a circuit analysis problem involving an 80k resistor, where a participant questions why the voltage across it is zero and why there is no current flowing through it. The conversation also touches on the energy stored in a capacitor and its relation to voltage, leading to further inquiries about calculations and assumptions in the context of an RC circuit.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant states that using KCL and KVL led to the conclusion that the voltage over the 80k resistor is zero, but seeks clarification on this result.
  • Another participant suggests that if the leads of a resistor are wired together, there would be no current flowing through it, implying a conceptual understanding of current flow.
  • There is a discussion about the application of KVL, with one participant questioning the method used to derive the equations and suggesting that the analysis could have been simplified.
  • A later post introduces a question about the energy in a capacitor, proposing a formula for calculating energy based on capacitance and voltage.
  • Subsequent replies indicate a correction regarding the formula for energy in a capacitor, with a participant acknowledging a mistake in their earlier understanding.
  • Another participant points out that there is no capacitor in the original schematic, questioning the relevance of the energy calculation to the initial problem.
  • One participant expresses confusion over their calculations related to the energy stored in the capacitor and seeks help in identifying the mistake.
  • A final reply criticizes the introduction of a second topic unrelated to the original post and suggests that the full context of the problem should be provided for clarity.

Areas of Agreement / Disagreement

Participants express differing views on the application of circuit analysis methods and the relevance of capacitor energy calculations to the original problem. There is no consensus on the correctness of the initial circuit analysis or the subsequent energy calculations.

Contextual Notes

The discussion includes unresolved assumptions about circuit configurations and the implications of using KVL and KCL. There are also limitations in the clarity of the original schematic and the relationship between the resistor and capacitor topics.

Jonas E
Messages
15
Reaction score
0

Homework Statement


I have the circuit in the picture below, and using KCL and KVL I found that the voltage over the 80k resistor is 0. However, I don't understand why this is correct. Can someone explain why there is no current through it?

Homework Equations


None

The Attempt at a Solution


I used the node voltage method to get 25ib + 1/(16k)-i0 = 0. After that I used KVL through the 80k resistor, 16k resistor and 1V source, which gave me 80k * ib - 1 + 1 = 0. So ib = 0.
circuit2.png
 
Physics news on Phys.org
Jonas E said:
Can someone explain why there is no current through it?
Imagine you took a resistor and wired its leads together. Why would there be any current flowing in it?

Jonas E said:
After that I used KVL through the 80k resistor, 16k resistor and 1V source, which gave me 80k * ib - 1 + 1 = 0. So ib = 0.
I guess you mean you used KVL for the two loops and "added" the equations together. There's no loop that takes you through each of those components.

You could have stopped at 80k*ib = 0.
 
milesyoung said:
Imagine you took a resistor and wired its leads together. Why would there be any current flowing in it?I guess you mean you used KVL for the two loops and "added" the equations together. There's no loop that takes you through each of those components.

You could have stopped at 80k*ib = 0.

Thanks for the reply. Could you also tell if the energy in a capacitor at time t equals half of its capacitance times its voltage at time t? So w(t) = 1/2 * C * v(t) ?
 
milesyoung said:

Sorry, I forgot to square the voltage. But is this correct then: w(t) = 1/2 * C * [v(t)] ^2 ? I couldn't understand the wikipedia article. You see, I used this formula, but it doesn't give me the right answer
 
Jonas E said:
You see, I used this formula, but it doesn't give me the right answer
Answer for what? There's no capacitor in your schematic.
 
milesyoung said:
Answer for what? There's no capacitor in your schematic.

EDIT: Ok, sorry again, but I just found out what I did wrong: When taking the square root, I forgot that there would be two answers. The negative one turned out to be the correct one. Thanks for helping me out figure out my original problem!

Sorry, the original post was just part of the problem.

I used that schematic to find Rth = 16k ohms and Vth = -19.8 V. I used this to make an RC circuit (C = 0.25 * 10^-6 F), which I solved to find that the capacitor's voltage is given by v(t) = [ 19.8 * (e^(-250t) - 1) ]. Everything up until this point was correct according to the solutions manual. The final question was to find how long it takes for the energy stored in the capacitor to reach 36 % of its final value. This is where I set up the equation w(t) = 0.36 * w(infinity). But for some reason this doesn't give me the correct answer. I used the following values:

w(t) = 0.5 * (0.25 *10^-6) * [ 19.8 * (e^(-250t) - 1) ]^2

w(infinity) = 0.5 * (0.25 *10^-6) * [ 19.8 * ( 0 - 1) ]^2 = 4.9005 * 10^-5 J

Could you help me find the mistake in my reasoning?
 
Last edited:
Jonas E. You are introducing a second topic unrelated to the original post. For this RC network you must start a new thread.

I'm not satisfied that your original circuit has been correctly dispensed with yet. I think you should post the whole exercise, not just a piece, so that we can see the full picture, rather than dealing with your uncertain interpretation of a piece out of context.
 

Similar threads

Replies
15
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 23 ·
Replies
23
Views
5K
  • · Replies 19 ·
Replies
19
Views
5K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
0
Views
2K