Can someone help me figure this out?

  • Thread starter Thread starter curiousgeorge99
  • Start date Start date
  • Tags Tags
    Figure
Click For Summary

Homework Help Overview

The discussion revolves around determining the necessary revolutions per minute for a Ferris wheel with a diameter of 15 meters to create a sensation of weightlessness at the topmost point. The problem involves concepts from circular motion and forces acting on a body in motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between linear velocity and angular velocity, with attempts to convert between units of measurement. There are questions about the meaning of calculated values and how to relate them to revolutions per minute.

Discussion Status

Some participants have provided guidance on using the relationship between linear and angular velocity, while others express confusion about the conversion process and the initial steps needed to solve the problem. Multiple interpretations of the relationships involved are being explored.

Contextual Notes

Participants mention the need for a free body diagram to analyze forces acting on a person at the top of the Ferris wheel, indicating that assumptions about forces and motion are under discussion. There is also a reference to textbook information that may not be fully understood by all participants.

curiousgeorge99
Messages
16
Reaction score
0

Homework Statement


How many revolutions per minute would a 15m diameter Ferris wheel need to make for a person to feel 'weightless' at the topmost point?


Homework Equations


F= mv~2/r - mg
v = 2pi r/ T


The Attempt at a Solution


I get 8.57 m/s using the equation F= mv~2/r - mg
I think I need to use v = 2pi r/ T to figure out T. If I do this, I get T=5.49. I have no idea if this is right. If it is, then I'm not sure what 5.49 represents and how to turn it into rev/minute. The answer is supposed to be 11 rev/min.
 
Physics news on Phys.org
do you know what the relationship between [tex]V[/tex] and [tex]\omega[/tex] is?
 
V = displacement / time elapsed,

W = number of radians / second

Is that right?

Acceleration is A = change in velocity / change in time
Angular accel. A = change in # of radians / change in time.

This is about all I know. I'm not sure how they are related or how you get rev/min from here.

Its probably staring me right in the face but I still can't see it
 
You are on the right track with mv^2/r = mg, but that solves for the linear/tangential velocity (in m/s). Remember to convert that to angular velocity (rad/s) on your way to finding rpm.
 
[tex]v=r\omega[/tex]

do you know the relationship between [tex]\omega[/tex] and rev/min?
 
Is the relationship between W and rev/min: 0.1047 rad/s = 1 rev/min.
 
curiousgeorge99 said:
Is the relationship between W and rev/min: 0.1047 rad/s = 1 rev/min.

yes, do you know why?
 
No, no idea why. I just have that at the front of my textbook.
 
curiousgeorge99 said:
No, no idea why. I just have that at the front of my textbook.

[tex]2 * \pi[/tex]rad/s = 1rev/s right? cause [tex]2 * \pi[/tex] is the whole circle
 
Last edited:
  • #10
ok, that makes sense!

thanks

I'm going to see if I can solve this problem now.
 
  • #11
nope, still lost!

I think I'm stuck on where to start.

I keep trying to figure out the velocity in m/s then convert to rev/min.

Is there a better way to do it?
 
  • #12
i have the same problem...
 
  • #13
can any1 help?
 
  • #14
try to do a free body diagram showing all forces when the person is at the top of the ferris wheel
then equate them
one of them will have what u want in it
and u are provided with what u don't know in the question

let us know if u still can't get it
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
17
Views
2K
  • · Replies 11 ·
Replies
11
Views
7K
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K