Can someone help me redraw this circuit.

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SUMMARY

The discussion centers on redrawing a circuit to clarify the arrangement of components in series and parallel. The user initially seeks reassurance about their circuit interpretation but ultimately resolves their query independently. They confirm the correctness of their redrawn circuit and proceed to calculate the current through resistor 5 using the current divider rule, noting that the current through resistor 6 is 1.64 mA. The conversation highlights the importance of practice in mastering circuit analysis.

PREREQUISITES
  • Understanding of circuit components, specifically resistors
  • Familiarity with series and parallel circuit configurations
  • Knowledge of the current divider rule
  • Basic skills in circuit diagram interpretation
NEXT STEPS
  • Study the current divider rule in detail
  • Learn about calculating potential difference in circuits
  • Explore advanced circuit analysis techniques
  • Practice redrawing complex circuit diagrams
USEFUL FOR

This discussion is beneficial for electrical engineering students, hobbyists working on circuit design, and anyone looking to improve their skills in circuit analysis and interpretation.

LakeMountD
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man I am not good at doing these circuits.. i do think i have it right however i want to be reassured before i drive this info into my head..

http://galileo.physics.fsu.edu/enc/60/b0693c1d166eb44f829042abcf6390a2cf5a73998caaf05a1d16890408211ac74fb5a1875d078912fd7a599483ded40f7806f73f3857b7e65b1628c75c29fe63f222626d31cef1695b9709989c1a225a

thanks guys.. basically redrawing it so you can see what is parallel and in series..
 
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its asking for a password and username
 
formulajoe said:
its asking for a password and username

oops sorry about that.. here it is
answered my own question lol..

http://img210.exs.cx/img210/2812/resistor6xg.gif
 
yep, that looks right. circuits are a snap with a little bit of practice.
 
OKay i got the right answer but now it is asking for the current through resistor 5. the current through resistor 6 is 1.64 mA.

then for b it wants the potential difference between point a and b.
 
You've got current through resistor 6. Then use current divider rule to get the current through resistor 5 (using R5 and Req3).
 

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