- #1

- 6

- 1

## Homework Statement

The question requires viewing the circuit diagram to start. An image is attached, it can also be viewed here (http://imgur.com/6Q0DCQ9).

The questions are:

a) Calculate the equivalent resistance ##R_T## of the 4 ##\parallel## 8 ohm combination.

b) Redraw the circuit with ##R_T## replacing the two parallel resistors.

c) What is the voltage at point X ?

## Homework Equations

Ohm's law ## V = I R ## , Resistance in parallel ## 1/R_T = 1/R_1 + 1/R_2 ## ,

## The Attempt at a Solution

a)

## 1/R_T = 1/4 + 1/8 ##

**## R_T = 2.7 ## Ohm**[/B]

b) I just re drew the circuit diagram the same, but instead of the two parallel resistors there is just one with a resistance of 2.7 Ohms.

c) This is where I am stuck. I can't work out how this circuit operates.

I take it the two batteries can't be in parallel because they are different voltages?

So will the current flow back through the 8 v battery and the voltage will drop to 4v at point Y ? And then the voltage stay at 12v at point X ? However now if I calculate the current at the resistors it's different.

I will be extremely grateful if someone can point me in the right direction on this.

Thanks in Advanced.