Can the Alternating Series Test Determine Divergence?

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SUMMARY

The discussion centers on the Alternating Series Test and its implications for determining the convergence or divergence of series. A sequence \( a_{n} \) that is non-negative and approaches zero can still lead to divergence in the series \( \sum (-1)^{n+1} a_{n} \) if the sequence does not satisfy the conditions of being strictly decreasing. The example provided, \( (1, 0, 1/2, 0, 1/3, 0, 1/4, 0, \ldots) \), illustrates a sequence that is non-decreasing and thus does not conform to the test's requirements, leading to divergence despite being null.

PREREQUISITES
  • Understanding of the Alternating Series Test
  • Familiarity with sequences and series in calculus
  • Knowledge of convergence and divergence criteria
  • Basic mathematical notation and limits
NEXT STEPS
  • Study the conditions for convergence in the Alternating Series Test
  • Explore examples of divergent series that meet initial conditions
  • Learn about other convergence tests such as the Ratio Test and Root Test
  • Investigate the implications of non-decreasing sequences in series
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Students of calculus, mathematicians studying series convergence, and educators teaching the principles of the Alternating Series Test.

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Homework Statement



Find a sequence [tex]a_{n}[/tex] which is non-negative and null but where [tex]\sum (-1)^{n+1} a_{n}[/tex] is divergent.

Homework Equations



Alternating series test:

Let [tex]a_{n}[/tex] be a decreasing sequence of positive real numbers such that [tex]a_{n}\rightarrowa[/tex] as [tex]n\rightarrow\infty[/tex]. Then the series [tex]\sum (-1)^{n+1} a_{n}[/tex] converges.

The Attempt at a Solution



I'm a bit confused by this one. If [tex]a_{n}[/tex] is non-negative and null then it seems like it's decreasing to zero, in which case it satisfies the alternating series test. So how can the sum diverge?!
 
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How about (1,0,1/2,0,1/3,0,1/4,0...)? It's null but nondecreasing. The (-1)^(n+1) doesn't help much does it?
 
Ah yeah i see. So you sort of pad it out with zeros to remove the minus terms. Thanks!
 

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