MHB Can the limit of (x,y) at (1,0) be found using l'hopital's rule?

  • Thread starter Thread starter brunette15
  • Start date Start date
  • Tags Tags
    Limit
Click For Summary
To find the limit of the function as (x,y) approaches (1,0), it's essential to verify that the limit is consistent across different paths. Attempts to apply L'Hôpital's rule have not yielded results, indicating a need for a different approach. It is suggested to evaluate the limit along the lines y = x - 1 and y = -x + 1 to check for consistency. The limit must be the same when approached from these paths to confirm its existence. Exploring these paths will clarify whether the limit can be determined effectively.
brunette15
Messages
58
Reaction score
0
I am trying to find the limit of the following:

lim(x,y)--> (1,0) ((x-y-1)2/(x+y-1)2)

I have had a few attempts trying to use l'hopital's rule but i don't seem to be getting anywhere...
 
Physics news on Phys.org
brunette15 said:
I am trying to find the limit of the following:

lim(x,y)--> (1,0) ((x-y-1)2/(x+y-1)2)

I have had a few attempts trying to use l'hopital's rule but i don't seem to be getting anywhere...
For this you need to show that the limit exists (and is the same) along all paths approaching it.

Hint: Approach the limit point along the line y = x - 1 and the line y = -x + 1. Is the limit the same in both cases?

-Dan
 

Similar threads