Can the limit of (x,y) at (1,0) be found using l'hopital's rule?

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SUMMARY

The limit of the function lim(x,y)→(1,0) ((x-y-1)²/(x+y-1)²) can be evaluated using L'Hôpital's Rule, but it requires confirming that the limit is consistent across different paths. Specifically, approaching the limit point along the lines y = x - 1 and y = -x + 1 yields different results, indicating that the limit does not exist. This conclusion is critical for understanding multivariable limits and the application of L'Hôpital's Rule in such contexts.

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brunette15
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I am trying to find the limit of the following:

lim(x,y)--> (1,0) ((x-y-1)2/(x+y-1)2)

I have had a few attempts trying to use l'hopital's rule but i don't seem to be getting anywhere...
 
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brunette15 said:
I am trying to find the limit of the following:

lim(x,y)--> (1,0) ((x-y-1)2/(x+y-1)2)

I have had a few attempts trying to use l'hopital's rule but i don't seem to be getting anywhere...
For this you need to show that the limit exists (and is the same) along all paths approaching it.

Hint: Approach the limit point along the line y = x - 1 and the line y = -x + 1. Is the limit the same in both cases?

-Dan
 

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