- #1

Spatulatr0n

- 4

- 0

So if the limit of a function is an imaginary number, does that mean that the limit does not exist? Or that it does not exist on the xy-plane, or what?

I mean...imaginary and complex numbers exist, we just can't graph them on a Cartesian plane, right? Right?

I've managed to confuse myself terribly.

Please, help my brain.