Can the Total Energy in a Spring Be Rearranged?

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SUMMARY

The total energy stored in a spring is expressed as (1/2)kA^2, where k represents the spring constant and A is the amplitude. The discussion clarifies that k can be defined as F/x, leading to the rearrangement (1/2)(FA^2/x). However, the correct interpretation of the energy equation requires understanding that F must equal mg when a mass is attached to a hanging spring. Thus, the expression (1/2)(mgA) is valid only under this specific condition.

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JustinLiang
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Homework Statement


Since the total energy in a spring is
(1/2)kA^2

Can we rearrange this...
given k=F/x
(1/2)(FA^2/x)

Since x is also the amplitude, we have:
(1/2)(FA)
(1/2)(mgA)

I am pretty sure this is wrong, but why?

Thanks
 
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JustinLiang said:

Homework Statement


Since the total energy in a spring is
(1/2)kA^2

Can we rearrange this...
given k=F/x
(1/2)(FA^2/x)

Since x is also the amplitude, we have:
(1/2)(FA)
yes, where F is the max force in the spring and A is the absolute value of x.
(1/2)(mgA)
Only if F = mg, as when a mass is attached from a hanging spring and released.
 

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